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Evgesh-ka [11]
3 years ago
11

First, she needs to find her resting heart rate by counting her pulse for one minute immediately after she wakes up for 5 days i

n a row. She finds her average resting heart rate to be 62 after
5 days and she remembers the last day's pulse was 58 and all the others were the same. Write and solve an equation to find what her pulse was on all the other days. Justify your answer by showing your steps. Put in Simple equation
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Answer:

63

Step-by-step explanation:

She finds her average resting heart rate to be 62 after  5 days.

That means, average of the 5 heart rate pulse=62

If the last day was 58 and all the other days were the same.

Let x be her pulse on the other days,

Then,

Average, 62=\dfrac{58+4x}{5}\\\text{Cross Multiply}\\58+4x=62 X 5\\\text{Suntract 58 from both sides}\\4x=(62X5)-58\\4x=310-58\\4x=252\\\text{Divide both sides by 4}\\x=63

Her pulse on all the other days is 63.

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Answer:

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Step-by-step explanation:

We have been given the trigonometric function \sin^2 x +\sinx-2

We can factor this by AC method. In AC method we multiply the term a and c and then write the middle term b in such a way that the sum/difference is equal to the product 'ac'

Using the method, we can write sinx as 2sinx -sinx

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Now, we group the first two terms and the last two terms

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Answer:

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(x-9)(x+2)

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