The dot product of the two vectors will be given as follows:
v*w=(-7i+4j)*(-6i+5j)
=(-7*(-6))i+(4*5)j
=-42i+20j
Hence the answer is:
v*w=(-42i+20j)
Let x be the number you want to find
435= x times 25 times 3
435= 75x
X= 435/75 =5.8 (ans)
Answer:
c.132
Step-by-step explanation:
so we are given the diameter which is 42m **the diameter is the straight line that passes through the middle of the circle**
but in order to find the circumference we need to find the radius **the radius is always half (1/2,0.5) of the diameter**
so we have to divide 42/2 which equals 21
now we need to set up the formula;
c=2πr/c=2xπxr **when unknown variables such as 'r' are next to another mathematical numeral such as the pi symbol you don't really have to but the multiplication symbol between them**
c=2π21
=131.946891451
and in your case, it seems we must round to the tenths place so the nine then "becomes a ten" and you're left with 132
good luck :)
i hope this helps
have a good one !!
Answer:
![a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]](https://tex.z-dn.net/?f=a%29%5C%20%5C%20%5Cbar%20x_m-%5Cbar%20x_f%3D67.03%5C%5C%5C%5Cb%29%5C%20%5C%20E%3D15.7416%5C%5C%5C%5Cc%29%5C%20%5C%20CI%3D%5B51.2884%2C%20%5C%2082.7716%5D)
Step-by-step explanation:
a. -Given that:
#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:
Hence, the pointer is estimator 67.03
b. The standard error of the point estimator,
is calculated by the following following:
-And the margin of error, E at a 99% confidence can be calculated as:
Hence, the margin of error is 15.7416
c. The estimator confidence interval is calculated using the following formula:
#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:
![CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x_m-%5Cbar%20x_f%5C%20%5Cpm%20z_%7B%5Calpha%2F2%7D%5Csqrt%7B%5Cfrac%7B%5Csigma_m%5E2%7D%7Bn_m%7D%2B%5Cfrac%7B%5Csigma_f%5E2%7D%7Bn_f%7D%7D%5C%5C%5C%5C%3D%28135.67-68.64%29%5Cpm%2015.7416%5C%5C%5C%5C%3D67.03%5Cpm%2015.7416%5C%5C%5C%5C%3D%5B51.2884%2C%20%5C%2082.7716%5D)
Hence, the 99% confidence interval is [51.2884,82.7716]
I guess you want the missing angle.
The missing angle is 83
