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4 years ago

Ch.5 test grade 4 Go math

Mathematics

1 answer:

jeka944 years ago

7 0

Do you have a question in math? Just comment it to me and I'll try my best to help :D

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P(t) = 2ť + 10<br> n(t) = 4<br> What’s the function (p+n) (t)?

Evgen [1.6K]

Answer:

$\boxed{\sf (p + n)(t) = 2t + 14}$

Given:

$\sf p(t) = 2t + 10 \\ \sf n(t) = 4$

To find:

$\sf (f + g)(x) = f(x) + g(x)$

Step-by-step explanation:

$\sf \implies(f + g)x = f(x) + g(x) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (2t + 10) + ( 4) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2t + 10 + 4 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2t + 14$

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3 years ago

HELP ASAP DUE IN 20 MINUTES

IrinaK [193]

Answer:

x = 3

< D = 26

< E = 54

Step-by-step explanation:

I did the math

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3 years ago

How do you find the arctan 4/3 ? (Without a calculator)

Soloha48 [4]

If arctan 4/3 = the tangent of that angle will be 4/3 , opposite 4 over adjacent 3

Now, you only have to take the sin of that angle it's opposite 4 over hypotenuse 5.

You will get that the answer is 4/5

hope this helps

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3 years ago

2 EASY QUESTIONS 6TH GRADE WILL GIVE BRAINLY

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Write and equation for the shift of the parent graph y=1/x

SashulF [63]

You can think of this equation as $\bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}$

and thus apply the transformations to it as such

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

1) D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7

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3 years ago