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Troyanec [42]
3 years ago
12

In how many ways can the letters of the word APPROXIMATION be arranged?

Computers and Technology
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer:

2494800

Explanation:

A lot of math and time.

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What kind of software would you recommend a company use if its employees are receiving e-mails that are potentially hazardous ?
scZoUnD [109]

Answer:

Microsoft project

Explanation:

I'm smart

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3 years ago
In an attempt to reach an all-time record for its premier, ads for the highly anticipated Avengers: Endgame are run on all the m
cricket20 [7]

Based on the contextual situation, the cable stations across the country from 8:00 p.m. to 10:00 p.m., or during <u>Late-fringe time</u>.

<h3>What is Late-Fringe Time?</h3>

Late Fringe time is a term used in television that describes the television hours that follow the prime time.

Generally, the prime period is usually between 8:00 p.m. to 10:00 p.m., while the Late Fringe time is around 11 p.m. to 1 a.m.

Hence, in this case, it is concluded that the correct answer is "<u>Late-Fringe period."</u>

Learn more about Television hours here: brainly.com/question/1006994

8 0
3 years ago
Create a Racket procedure compute_pos that reads numbers from the keyboard until 0 is read, count how many positive numbers are
Artyom0805 [142]

Answer:

import java.util.Scanner;

public class Solution {

   public static void main(String args[]) {

       compute_pos();

     }

     

     public static void compute_pos(){

     Scanner scan = new Scanner(System.in);

     int sum = 0;

     int counter = 0;

     // Prompt the user to enter an input

     System.out.println("Enter your value");

     // user input is assign to the variable value

     int value = scan.nextInt();

     

     while(value != 0){

         if (value > 0){

             sum += value;

             counter++;

         }

         System.out.println("Enter your value");

         value = scan.nextInt();

     }

     // Display the value of sum to the user

     System.out.println("The sum of the positive number is: " + sum);

     // Display the value of counter to the user

     System.out.println("The number of positive number is: " + counter);

   }

}

Explanation:

The first line import the Scanner class which allow the program to read input from the user. The class Solution is then defined. Then the main method which signify the beginning of execution in the program is defined. A method is called inside the main method.

The method compute_pos is defined. Inside the compute_pos method, a scanner object scan is declared to accept input from the user via the keyboard.

The variable sum and counter is declared and assigned to 0.

A prompt is displayed to the user to input a value. The user input is accepted and stored in the variable value.

Then a while loop is use to check the user input if it is not equal to zero. If it is equal to zero, the loop will end. Inside the loop, we first check to see if the user input is greater than 0, if it is, we add it to the variable sum and increase our counter by 1. At the end of the loop, a prompt is again display to accept input from the user.

Outside the loop, we display the sum and counter to the user.

8 0
4 years ago
Write a program that reads a list of words. Then, the program outputs those words and their frequencies. If the input is 5 hey h
zysi [14]

Answer:

/ declare the necessary header files.

#include <iostream>

#include <string>

#include <vector>

using namespace std;

// declare the main function.

int main()

{

// declare a vector.

vector<string> words;

vector<int> counts;

// declare variables.

int size;

string str;

cin >> size;

// start the for loop.

for(int i = 0; i < size; ++i)

{

// input string.

cin >> str;

words.push_back(str);

}

// start the for loop.

for(int i = 0; i < size; ++i)

{

int count = 0;

// start the for loop.

for(int j = 0; j < words.size(); ++j)

{

// check the condition.

if(words[j] == words[i])

{

count++;

}

}

counts.push_back(count);

}

// start the for loop.

for(int i = 0; i < size; ++i)

{

// display result on console.

cout << words[i] << "\t" << counts[i] << endl;

}

return 0;

}

Explanation:

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The best defense against injection attacks is to
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The best defense against injection attacks is to develop secure habits and adopt policies and procedures that minimize vulnerabilities. Staying aware of the types of attacks you're vulnerable to because of your programming languages, operating systems and database management systems is critical.
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