Answer:
The MSS is 1455
Explanation:
MSS or maximum segment size is the total number of data transferred minus the TCP and IP header. The total number of transmitted frames in a switch network is between 64 bytes to 1518 bytes with a header and trailer. The MSS does not exclude this data-link layer effect but only the transport layer like TCP and UDP, and IP address header, unlike the mtu (maximum transfer unit) which involves all headers.
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Answer:
brand community
Explanation:
Many company websites are now designed to do more than just sell a product. These websites, known as brand community websites, attempt to build closer customer relationships and generate engagement with and between the brand and its customers. These online communities bring together consumers who have shared interests in a brand or product. One advantage of online brand communities is that they reduce customer support costs as the business has more engagement with their customers.This also helps the business to retain customers through brand improvement centered around the customer's actual needs.
Answer:
The person left
Explanation:
The person could of been banned or deleted their account
Gettier contributed to what we know about the exemplar model, while Rosch contributed to what we know about the prototype model. Prototype and exemplar theories are both versions of statistical theories of concepts. Prototype theories hold that concepts represent categories by means of a summary of the typical properties that category members possess, while exemplar theories hold that concepts represent categories by means of a cluster of individual category members that may be used to extract the statistical central tendency of the category.
