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vlada-n [284]
3 years ago
15

Consider the following method, inCommon, which takes two Integer ArrayList parameters. The method returns true if the same integ

er value appears in both lists at least one time, and false otherwise.
public static boolean inCommon(ArrayList a, ArrayList b)
{
for (int i = 0; i < a.size(); i++)
{
for (int j = 0; j < b.size(); j++) // Line 5
{
if (a.get(i).equals(b.get(j)))
{
return true;
}
}
}
return false;
}
Which of the following best explains the impact to the inCommon method when line 5 is replaced by for (int j = b.size() - 1; j > 0; j--) ?
A. The change has no impact on the behavior of the method.
B. After the change, the method will never check the first element in list b.
C. After the change, the method will never check the last element in list b.
D. After the change, the method will never check the first and the last elements in list b.
E. The change will cause the method to throw an IndexOutOfBounds exception.
Computers and Technology
1 answer:
sp2606 [1]3 years ago
6 0

Answer:

The answer is "Option b".

Explanation:

In the given code, a static method "inCommon" is declared, that accepts two array lists in its parameter, and inside the method two for loop is used, in which a conditional statement used, that checks element of array list a is equal to the element of array list b. If the condition is true it will return the value true, and if the condition is not true, it will return a false value. In this, the second loop is not used because j>0 so will never check the element of the first element.

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Answer:

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Code:

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<u><em /></u>

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