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What is the height of a rectangular prism that has a volume of 192 cubic feet and a base with an area of 48 square feet? Explain

Harman [31]

The formula for volume is length × width × height, so this is the same as area of cross section × height. So, if the base of the rectangular prism (the cross section) has an area of 48 square feet, then 48 × the height = 192 cubic feet. Working backwards, we can find out the height (h will stand for height):
48×h=192
h=192÷48
h=4
Therefore, the height of the rectangular prism is 4 feet

6 0

3 years ago

Jessica was sitting in row 9, seat 3 at a soccer game when she discovered her ticket was for row 1, seat 1. Write a rule to desc

Westkost [7]

rule is to shift 8 units left & , shift 2 units down , Correct option C) T<-8,-2> (Jessica) ,

<u>Step-by-step explanation:</u>

Here we have , Jessica was sitting in row 9, seat 3 at a soccer game when she discovered her ticket was for row 1, seat 1. We need to Write a rule to describe the translation needed to put her in the proper seat. Let's do this:

Suppose the above problem in coordinate system where we have a point $P(9,3)$ , And we need to write rule for translation of this point to $Q(1,1)$ .

Let , $(x,y)=(9,3)$ , Now shift 8 units left i.e.

⇒ $(x,y)=(9,3)$

⇒ $(x-8,y)=(9-8,3)$

⇒ $(x-8,y)=(1,3)$

Now , shift 2 units down i.e.

⇒ $(x-8,y)=(1,3)$

⇒ $(x-8,y-2)=(1,3-2)$

⇒ $(x-8,y-2)=(1,1)$

Therefore , rule is to shift 8 units left & , shift 2 units down , Correct option C) T<-8,-2> (Jessica) ,

4 0

3 years ago

One of the students is chosn at random. What is the probability of picking a student who sciored above 65

Andrews [41]

Answer: 7 / 18

Step-by-step explanation:

There were 18 students.

Out of them, the scores above 65 are:

73, 73, 69, 68, 71, 76, 70

There are 7 of them.

Probability of picking someone who scored higher than 65 is:

= Number of people who scored above 65/ Total number who took the test

= 7 / 18

6 0

3 years ago

For this equation, tell whether it is always true, sometimes true, or nevertrue.

dybincka [34]

To answer the question we make the sum on the left side of the equation:

$\begin{gathered} \frac{1}{2}y+5=\frac{y+10}{2} \\ \frac{y}{2}+5=\frac{y+10}{2} \\ \frac{y}{2}+\frac{10}{2}=\frac{y+10}{2} \\ \frac{y+10}{2}=\frac{y+10}{2} \end{gathered}$

Since both sides are exactly the same. this equation is always true.

3 0

1 year ago

Order the values from least to greatest: 8, 4, -5, 12, -14, 3 -14, -5, 3, 4, 8, 12 -5, -14, 3, 4, 8, 12 12, -14, -5, 3, 4, 8 3,

erma4kov [3.2K]

Answer:

all work is shown and pictured

6 0

4 years ago

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