Answer:
1000+150=1150+150=1300+150=1450+150=1600+150=1750+150=1900
3000+100=3100+100=3200+100=3300+100=3400+100=3500+100=3600
1900=2050+300=2350=2650=2950+150=3100+300=3400+600=4000
3600=3700+200=3900=4100=4300+100=4400+200=4600+400=5000
4000=4600=5200=5800+300=6100=6400+150=6550=6700=6850=7000
5000=5400=5800=6200+200=6400=6600+100=6700=6800=6900=7000
12+4+4
"The sum of two numbers is 20" can be translated mathematically into the equation:
x + y = 20.
"... and their difference is 10" can be translated mathematically as:
x - y = 10
We can now find the two unknown numbers, x and y, because we now have a system of two equations in two unknowns, x and y. We'll use the Addition-Subtraction Method, also know as the Elimination Method, to solve this system of equations for x and y by first eliminating one of the variables, y, by adding the second equation to the first equation to get a third equation in just one unknown, x, as follows:
Adding the two equations will eliminate the variable y:
x + y = 20
x - y = 10
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2x + 0 = 30
2x = 30
(2x)/2 = 30/2
(2/2)x = 15
(1)x = 15
x = 15
Now, substitute x = 15 back into one of the two original equations. Let's use the equation showing the sum of x and y as follows (Note: We could have used the other equation instead):
x + y = 20
15 + y = 20
15 - 15 + y = 20 - 15
0 + y = 5
y = 5
CHECK:
In order for x = 15 and y = 5 to be the solution to our original system of two linear equations in two unknowns, x and y, this pair of numbers must satisfy BOTH equations as follows:
x + y = 20 x - y = 10
15 + 5 = 20 15 - 5 = 10
20 = 20 10 = 10
Therefore, x = 15 and y = 5 is indeed the solution to our original system of two linear equations in two unknowns, x and y, and the product of the two numbers x = 15 and y = 5 is:
xy = 15(5)
xy = 75
30% are wearing blue
0.125....12.5% are wearing red
100 - (30 + 12.5) = 100 - 42.5 = 57.5% are wearing white <=
Answer:
Rhombus
Step-by-step explanation:
It does not have congruent diagonals
1st is 1 1/2 2nd is 2 and 3 is 2