<span>3-2(Cosx)^2 - 3Sinx = 0.
Recall (Sinx)^2 + (Cosx)^2 = 1.
Therefore (Cosx)^2 = 1 - (Sinx)^2
Substitute this into the question above.
</span><span>3-2(Cosx)^2 - 3Sinx = 0
3 - 2(1 - (Sinx)^2) - 3Sinx = 0 Expand
3 - 2 + 2(Sinx)^2 - </span><span><span>3Sinx = 0</span>
1 + 2(</span><span>Sinx)^2 - 3Sinx = 0 Rearrange
2(Sinx)^2 </span><span><span>- 3Sinx + </span>1 = 0
Let p = Sinx
2p^2 - 3p + 1 = 0 Factorise the quadratic expression
2p^2 - p - 2p +1 = 0
p(2p -1) - 1(2p -1) = 0
(2p-1)(p -1) = 0
Therefore 2p-1=0 or (p-1) = 0
2p=0+1 or (p-1) = 0
2p=1 or p = 0 +1.
p=1/2 or p = 1 Recall p = Sinx
Therefore Sinx = 1/2 or 1.
For 0<u><</u>x<u><</u>360
Sinx =1/2, x = Sin inverse (1/2) , x = 30,
(180-30)- 2nd Quadrant = 150 deg
Sinx = 1, x = Sin inverse (1) , x = 90
Therefore x = 30,90 & 150 degrees.
Cheers.</span>
7/6
The slope of the equation in the form y=Mx+c is m
Parallel lines have Same gradient
Which makes gradient 7/6
Please mark as brainliest
If the equation of a line is written in the
form,
is the y-intercept.
The y-intercept is -1. The line crosses the y-axis at the point (0,-1).
Answer:
dont really understand your question but 20 months is
608.334 days and 86.9049 months
Answer:
Q' (12,8) , R'( 24,20) and S' (24,8)
Step-by-step explanation:
Here, we want to get the coordinates of the image after dilating the pre-image by a scale factor of 4
What we have to do here is to multiply each of the coordinate on the pre-image by 4
We have this as;
Q' = (4*3, 2 * 4) = (12,8)
R' = (4*6, 4*5) = (24,20)
s' = (4*6, 4*2) = (24,8)
