To get the equation of the line, you need two points that belong to this line.
From the given graph, we can choose any two points: (0,-4) and (-2,0)
The general for of the linear straight line is:
y = mx + c where m is the slope and c is the y-intercept
First, we will calculate the slope using the following rule:
slope = (y2-y1) / (x2-x1)
slope (m) = (0--4) / (-2-0) = 4/-2 = -2
The equation of the line now is: y = -2x + c
Then, we will get the value of the c. To do so, we will choose any point and substitute in the equation. I will choose the point (0,-4)
y = -2x + c
-4 = -2(0) + c
c = -4
Based on the above calculations, the equation of the line is:
y = -2x - 4
Answer: The required solution is 
Step-by-step explanation:
We are given to solve the following differential equation :
where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.
From equation (i), we have
Integrating both sides, we get
![\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]](https://tex.z-dn.net/?f=%5Cint%5Cdfrac%7Bdy%7D%7By%7D%3D%5Cint%20kdt%5C%5C%5C%5C%5CRightarrow%20%5Clog%20y%3Dkt%2Bc~~~~~~%5B%5Ctextup%7Bc%20is%20a%20constant%20of%20integration%7D%5D%5C%5C%5C%5C%5CRightarrow%20y%3De%5E%7Bkt%2Bc%7D%5C%5C%5C%5C%5CRightarrow%20y%3Dae%5E%7Bkt%7D~~~~%5B%5Ctextup%7Bwhere%20%7Da%3De%5Ec%5Ctextup%7B%20is%20another%20constant%7D%5D)
Also, the conditions are
and
Thus, the required solution is
F(g(-1))
g(-1) = 3(-1) = -3
f(-3) = 2(-3) -1 = -6 -1 = -7
Answer:
The answer is 25g^R4
Step-by-step explanation:
When you solve the equation, it becomes 25g^R4, it doesn't result in a whole number.
