Question

The perimeter of a rectangle is equal to 4040. if the length is halved and the width is divided by 3, the new perimeter is decreased by 2424. what is the length of the original rectangle?

Answer 1

New perimeter is 4040-2424= 1616
original, let x and y be length and width
2x + 2y = 4040
new
2x/2 +2y/3 = 1616
x +2y/3 = 1616
x = 1616 - 2y/3
sub this x value into first eq
2(1616-2y/3) + 2y = 4040
3232 - 4y/3 + 2 = 4040
put like terms together
-4y/3+2y=4040-3232
2y/3=808
multiply both sides by 3
2y = 2424
divide both sides by 2
y=1212

sub this y value into any eq. i chose eq 1
2x+2(1212)= 4040
2x = 4040 - 2(1212)
2x = 1616
x = 808

so the length is 808 and the width is 1212