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2 years ago

12

Assuming there are no reflections or dilations explain how you would write the equation of the function whose graph is sketched

below

1 answer:

Fantom [35]2 years ago

6 1

Answer:4

Step-by-step explanation:

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What do you meen they are numbers

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The radio is of a circle is 3 millimeters what is the circles circumference

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c = 2(3.14)(radius)

c = 2(3.14)(3)

<em>multiply all those numbers together to get your circumference.</em>

c = 18.84.

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What would the unit rates be for a person who jogged 500 meters in 4 minutes?

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3 years ago

Which expression is equivalent to ( xy -6)2 for all values of x and y where the expression is defined?

hichkok12 [17]

Answer:

( x y -6)² = x² y² - 12 xy + 36

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the expression ( x y -6)²

Apply formula (a-b)² = a² -2ab + b²

( x y -6)² = (xy)² - 2 × xy× 6 + (6)²

= x² y² - 12 xy + 36

( x y -6)² = x² y² - 12 xy + 36

4 0

3 years ago

Read 2 more answers

What equation is graphed in this figure?

topjm [15]

Answer:

The third equation: $y+2=-3(x-1)$

Step-by-step explanation:

The two points on the line are $(-1,4)$ and $(1,-2)$ .

Slope of the line passing through two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

$m=(y_{2} -y_{1})/ (x_{2} -x_{1})$

Here, $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are $(-1,4)$ and $(1,-2)$ .

Therefore, slope is equal to, $m=(-2-4 )/ (1-(-1)$

$m=-6/2$

$m=-3$

Now, equation of a straight line with slope m and points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

$y-y_{1}=m(x-x_{1})\\y-y_{2}=m(x-x_{2})$

Now, if we use the 2nd form, then $x_{2}=1,y_{2}=-2$ .

So, the equation is given as :

$y-(-2)=-3(x-1)\\y+2=-3(x-1)$

8 0

3 years ago