The area is 36 units squared.
You have three ways you can solve this question.
Method 1:
Split the rhombus into two equal triangles.
You will get triangle ACD and triangle ACB.
Count the base length and height length of each triangle using the diagram.
You will get base = 6 units and height = 6 units. Plug this into the area of a triangle and then multiply it by 2.
A = bh/2 * 2
A = 6(6) / 2 * 2
A = 36 / 2 * 2
A = 18 * 2
A = 36
Method 2:
Calculate the length of DP.
The length of line segment DP is √28.8
Calculate the length of DC.
The length of line segment DC is 3√5
Put into equation A = bh.
A = bh
A = 3√5(√28.8)
A = 36
Method 3:
Calculate the length of each diagonal and put into formula A = 1/2(d1 * d2)
Diagonal DB = 12 units
Diagonal AC = 6 units
A = 1/2(d1 * d2)
A = 1/2(12 * 6)
A = 1/2(72)
A = 36
I love procrastinating my history essay for this :D
Answer:
(7 x + 6 y)^2
Step-by-step explanation:
Factor the following:
49 x^2 + 84 x y + 36 y^2
The coefficient of x^2 is 49 and the coefficient of y^2 is 36. The product of 49 and 36 is 1764. The factors of 1764 which sum to 84 are 42 and 42. So 49 x^2 + 84 x y + 36 y^2 = 49 x^2 + 42 x y + 42 x y + 36 y^2 = 7 x (7 x + 6 y) + 6 y (7 x + 6 y):
7 x (7 x + 6 y) + 6 y (7 x + 6 y)
Factor 7 x + 6 y from 7 x (7 x + 6 y) + 6 y (7 x + 6 y):
(7 x + 6 y) (7 x + 6 y)
(7 x + 6 y) (7 x + 6 y) = (7 x + 6 y)^2:
Answer: (7 x + 6 y)^2
Answer:

Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.
Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.
Now, since we know the end behaviours, let's find the asymptotic behaviours.
As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.
So, our range would be:
Answer:
1. 8x+9
2. 3x + 11
3. 9x + 8
4. 11x+9
5. 6x
6. 10x+ 8
7. 7x+7
Step-by-step explanation:
Answer:
if a z-score is equal to +1, it is 1 standard deviation above the mean.
Step-by-step explanation: