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Gekata [30.6K]
3 years ago
13

What is $640, 3%, 2 years

Mathematics
1 answer:
elena55 [62]3 years ago
5 0
<span>$38.40 is the simplest interest. </span>
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The safe load for a certain horizontal beam used to hold up part of a building varies inversely as the length between the
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The statement is true.

Answer: Option 1.

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An horizontal beam is constantly flat and has a consistent cross-segment. Notwithstanding normal shaft parameters, bar has the accompanying properties: Direction. A flat shaft might be situated either along the worldwide X-hub or worldwide Y-pivot.

A horizontal beam is used to hold a building up right and to give the support to the building. But the length of the horizontal beam differs in an inverse way between the supports.

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Simplify 12/5(10/3b+15/4) .
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Step 1. Simplify 10/3b to 10b/3
12/5(10b/3 + 15/4)
Step 2. Distribute 
8b + 9

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Distance Which expression could help you find the distance between (10, 4) and (–6, 4)? |10| + |–4| |10| + |4| |–6| + |4| |10| +
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Step-by-step explanation:

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3 years ago
Suppose that scores on the mathematics part of a test for eighth-grade students follow a Normal distribution with standard devia
riadik2000 [5.3K]

Answer:

We need an SRS of scores of at least 153.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large an SRS of scores must you choose?

This is at least n, in which n is found when M = 20, \sigma = 150. So

M = z*\frac{\sigma}{\sqrt{n}}

20 = 1.645*\frac{150}{\sqrt{n}}

20\sqrt{n} = 1.645*150

\sqrt{n} = \frac{1.645*150}{20}

\sqrt{n} = 12.3375

(\sqrt{n})^{2} = (12.3375)^{2}

n = 152.2

Rounding to the next whole number, 153

We need an SRS of scores of at least 153.

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