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Alinara [238K]
2 years ago
8

Which choice is similar to the figure shown?

Mathematics
1 answer:
IRINA_888 [86]2 years ago
8 0

Answer:

The parallelogram whose sides are 5 and 20  is similar

Step-by-step explanation:

The parallelogram whose sides are 5 and 20  is similar to the given parallelogram whose sides are 2 and 8 because the figures are the same shade and corresponding sides are proportional.

 \frac{2}{5} = \frac{8}{20}                 \frac{2}{4} \neq \frac{8}{18}

 \frac{2}{5} =\frac{2}{5}                   \frac{2}{4} \neq \frac{8}{4}

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Find the length of each arc, Round your answas to the nearest tenth. Use 3.14 for
quester [9]

Answer:

58.6 cm;

20.1 m

Step-by-step explanation:

✔️Length of arc = θ/360 × 2πr

Where,

θ = 240°

r = 14 cm

π = 3.14

Plug in the values:

Length of arc = 240/360 × 2 × 3.14 × 14

= 58.6133334 = 58.6 cm (nearest tenth)

✔️Length of arc = θ/360 × 2πr

Where,

θ = 105°

r = 11 m

π = 3.14

Plug in the values:

Length of arc = 105/360 × 2 × 3.14 × 11

= 20.1483334 = 20.1 m (nearest tenth)

3 0
4 years ago
Answer this please I will give brainliest
frozen [14]

40 Butterflies at Swallowtail :D

7 0
3 years ago
Read 2 more answers
A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0
2 years ago
Suppose that YM has a length of 12in and its distance from point L is 5in find the radius of circle L to the nearest tenth
sashaice [31]
We know that
applying the Pythagoras theorem
LM²=LV²+VM²
LM is the radius of the circle
LV=5 in
VM=12/2----> 6 in
so
LM²=5²+6²-----> LM²=61------> LM=7.81 in------> LM=7.8 in

the answer is
7.8 in
8 0
3 years ago
Find the values of the three missing values in the parallelogram the diagram is not to scale
Naddika [18.5K]
Parallelogram so opposite sites are parallel
then
<1 = 113
<2 = 45
<3 = 22

hope it helps
3 0
3 years ago
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