<span><span>1.)From the Insert tab, select the Shapes command. A drop-down menu will appear.
</span><span>2.)Select the desired shape
3.)</span></span>Click and drag<span> the slide to create the shape. You may need to move or resize the shape so it points to the desired part of the image.
4.)</span><span>f you want your callout to contain text, start typing while the shape is selected.
5.)</span><span>From the </span>Format<span> tab, you can use the options in the </span>Shape Styles<span> group to customize the appearance of the shape. You can also adjust the font from the Home tab</span>
Answer:
if you are finding to be a pilot you can find it at jinnah airport
Explanation:
Use the following rules:
- The sum of currents that enter and exit a node (junction) is always zero. So if you have 3 wires that connect, through one flows 2A, the other 3A, then the third must deliver 5A (taking the direction into account!)
- The sum of voltages across different components should always add up. So if you have a battery of 10V with two unknown resistors, and over one of the resistors is 4V, you know the other one has the remaining 6V.
- With resistors, V=I*R must hold.
With these basic rules you should get a long way!
To keep the medical records confidential otherwise, hackers would take advantage of them and sell them to the highest bidder
Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.
