Vcylinder-Vsphere=water
Vcylinder=hpir^2
Vsphere=(4/3)pir^3
given
cylinderradius=30 and h=100
Vcylinder=100pi30^2=100pi900=90000pi
let's leave it in terms of pi for more exactness
sphereradius=12
Vsphere=(4/3)pi12^3=2304pi
cylinder-sphere=90000pi-2304pi=87696pi
using pi=3.14
water=275365.44 cubic cm
last option is corrrect
Answer:
hello, i don't know what is answer, beacose im Ukrainian, sorry
Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
(a) So the top of the hill is 365 feet above sea level.
(b) Checkpoint 5 is 185 feet higher than checkpoint 2.
Step-by-step explanation:
<u>Solution for (a):</u>
<u />
Checkpoint 2 is -218 feet above sea level.
The top of a hill rises 583 feet above Checkpoint 2.
The altitude of the top of the hill = -218 + 583 = 365
So the top of the hill is 365 feet above sea level.
<u>Solution for (b):</u>
<u />
Checkpoint 2 is -218 feet above sea level.
Checkpoint 5 is -33 feet above sea level.
Checkpoint 5 is -33 - -218 = 185 feet higher than checkpoint 2.
Answer:
Two consecutive integers are of the form
x and x + 1
Their product is equal to 56
x(x + 1) = 56
Solve and find the two numbers x and x + 1. The above equation may be written as follows
x2 + x - 56 = 0
Factor and solve
(x - 7)(x + 8) = 0
solutions: x = 7 , x = -8
x= - 8 is not valid since the number sought must be positive. Hence
x = 7 and x + 1 = 8 are the two consecutive numbers.
Step-by-step explanation:
