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aleksandr82 [10.1K]
3 years ago
15

PLZZ HELP Which two numbers on the number line have an absolute value of 1.25? Select the location of both numbers on the number

line.
Mathematics
2 answers:
fgiga [73]3 years ago
8 0

Answer:

-1.25 and 1.25

Step-by-step explanation:

because if it were on a number line it would be negative and positive

i hope this helps also i know it is right because i did the test in k 12 and yah

MaRussiya [10]3 years ago
4 0

Answer:

-1.25

Step-by-step explanation:

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Chapter 2
Mashutka [201]

Answer:

11.20

Step-by-step explanation:

Multiply both equations by 100:

19.99=1999

8.79=879

1999-879=1120

Divide by 100:

1120/100=11.20 saved ................

5 0
2 years ago
A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature
Westkost [7]

Answer:

(a) The value of <em>k</em> is \frac{1}{15}.

(b) The probability that at most three forms are required is 0.40.

(c) The probability that between two and four forms (inclusive) are required is 0.60.

(d)  P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

Step-by-step explanation:

The random variable <em>Y</em> is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of <em>k</em>.

\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}

Thus, the value of <em>k</em> is \frac{1}{15}.

(b)

Compute the value of P (Y ≤ 3) as follows:

P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\   =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 to be the pmf of Y it has to satisfy the conditions:

  1. P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\
  2. \sum P(y)=1

<u>Check condition 1:</u>

y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0

Condition 1 is fulfilled.

<u>Check condition 2:</u>

\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1

Condition 2 is not satisfied.

Thus, P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

7 0
2 years ago
A circle has a radius of 9 ft.
Alexxx [7]
Formula for circl area
pi times radius^2
pi=aprox 3.14 in this problem
area=3.14 times radius^2
radius=9
area=3.14 times 9^2
area=3.14 times 81
area=254.34 square feet or
254.34 ft^2
5 0
3 years ago
Read 2 more answers
When measuring forecast error, which forecasting error expresses the forecast error as a percentage from the mean?
oee [108]
Mean Absolute Percent Error, MAPE
4 0
3 years ago
The Fort Worth Zoo had 6,195 visitors last week. The zoo is open seven days a
umka21 [38]

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equation:

7N = 6195

where N is the number of people that would show up to the zoo on a given day.

Dividing both sides by 7 will give us the answer:

N = 885

3 0
3 years ago
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