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Greeley [361]
3 years ago
13

Can someone explain to me how to answer this problem in simple ways? (I get really confused when it comes to math) A communicati

ons satellite transmits a radio wave at a frequency of 5 • 109 Hz. What is the signal’s wavelength? Assume the wave travels in a vacuum.
Physics
1 answer:
pishuonlain [190]3 years ago
4 0
When I find a problem like this, I find it helpful to think about what I know and what equation will help me.

The question tells us the frequency of the wave (5 \times 10^{-9}) Hz. We want to work out the wavelength. What equation links these two quantities?

Wave Speed = Frequency x Wavelength
(we know all electromagnetic waves travel at the speed of light in a vacuum)

(3 \times 10^8) = (5 \times 10^{-9}) \times \lambda
and then divide by (5 \times 10^{-9}) to get the wavelength.

Wavelength = 6 \times 10^{16} m<u />
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Newton's second law of motion can also be described as...
Irina-Kira [14]

Answer


B. F=ma



Explanation

The Newton's laws of motion tries to explain the how bodies behave and the energy changes when theys are in motion. For the 3 of them to hold, the bodies must be moving in a straight line and with constant velocity.

The second one states that, "the change of momentum of a moving body is directly proportional to the force producing it and it takes place to the direction of force."

From the choices given, the appropriate answer is B. F=ma

6 0
3 years ago
Car a with mass 1,783 kg collides with stationary 1600 kg car b. they become locked together after the collision and move with s
ValentinkaMS [17]

The initial speed of car A is 15.18 m/s.

Momentum is defined as mass in motion. If there are two objects (the two objects in motion or only one object in motion and the other in stationary) that collide and no other forces work in the system, the law of momentum conservation applies in the system.

p=p'

pa+pb = pa'+pb'

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

  • ma = mass of object A (kg) = 1,783 kg
  • mb = mass of object B (kg) = 1,600 kg
  • va = speed of object A before collides (m/s)
  • va' = speed of object A after collides (m/s) = 8 m/s
  • vb = speed of object B before collides (m/s) = 0 m/s
  • vb' = speed of object B after collides (m/s) = 8 m/s
  • p = momentum before collision (Ns)
  • p' = momentum after collision (Ns)

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

(1,783×va) + (1,600×0) = (1,783×8) + (1,600×8)

(1,783×va) + 0 = 14,264+12,800

(1,783×va) = 27,064

va \:=\: \frac{27,064}{1.783}

va = 15.18 m/s

Learn more about The law of momentum conservation here: brainly.com/question/7538238

#SPJ4

3 0
1 year ago
Please help with these questions
lord [1]
When do you gotta turn it in?
8 0
2 years ago
Use a(t) = -32 feet per second per second as the acceleration due to gravity. (Neglect air resistance.) -With what initial veloc
Kitty [74]

Answer:

u= 187.61 ft/s

Explanation:

Given that

g= - 32 ft/s²

The maximum height ,h= 550 ft

Lets take the initial velocity = u ft/s

We know that

v²=u² + 2 g s

v=final speed ,u=initial speed ,s=height

When the object reach at the maximum height then the final speed of the object will become zero.

That is why

u²= 2 x 32 x 550

u²= 35200

u= 187.61 ft/s

That is why the initial speed will be 187.61 ft/s

7 0
3 years ago
Read 2 more answers
Two objects of the same mass are on two different planets. Planet A has a force of gravity that is weaker than that of planet B.
iris [78.8K]
C) The weight of the object on planet A will be less than the weight of the object on planet B.


This happened because: when gravitational pull of a planet is weak, an object will weigh less as a result of less gravity forcing it down to the ground.
7 0
3 years ago
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