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Greeley [361]
3 years ago
13

Can someone explain to me how to answer this problem in simple ways? (I get really confused when it comes to math) A communicati

ons satellite transmits a radio wave at a frequency of 5 • 109 Hz. What is the signal’s wavelength? Assume the wave travels in a vacuum.
Physics
1 answer:
pishuonlain [190]3 years ago
4 0
When I find a problem like this, I find it helpful to think about what I know and what equation will help me.

The question tells us the frequency of the wave (5 \times 10^{-9}) Hz. We want to work out the wavelength. What equation links these two quantities?

Wave Speed = Frequency x Wavelength
(we know all electromagnetic waves travel at the speed of light in a vacuum)

(3 \times 10^8) = (5 \times 10^{-9}) \times \lambda
and then divide by (5 \times 10^{-9}) to get the wavelength.

Wavelength = 6 \times 10^{16} m<u />
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A uniform rod of length L, mass M, is suspended by two thin strings. Which of the following statements is true
Fantom [35]

Answer:

(d) not enough info

Explanation:

because it doesn't specify where the strings are attached

if it was the two ends of the rod then T1 would be equal to T2

6 0
3 years ago
a rectangular block weighs 240N. The area of the block in contact with the floor is 20cm2 calculate the pressure on the floor
Romashka [77]

Answer:

The pressure on the floor is 12 Pascal(Pa).

Explanation:

Given,

Force (F) = 240N

Area (A) = 20 cm^2

Pressure (P) = ?

we know that,

P = F/A

= 240/ 20

= 12 Pa

8 0
3 years ago
Si uno de los valores de la tabla no se visualiza en el gráfico, ¿Cómo lo encontramos?
ivanzaharov [21]
No, no me habla espanol. yo soy ingles
6 0
3 years ago
From 0 seconds to 4 seconds is the acceleration positive or negative?
Alenkinab [10]

Answer:

From 0 -4 seconds the acceleration is positive. (The graph is going upwards.)

From 6-10 seconds the acceleration is negative. (The graph is going downwards.)

7 0
3 years ago
An airplane is heading due south at a speed of 560 km/h . If a wind begins blowing from the southwest at a speed of 80.0 km/h (a
polet [3.4K]

Answer:

the magnitude of Vpg = 493.711 km/h

Explanation:

given data

speed Vpg = 560 km/h

speed Vwg = 80 km/h

solution

we get here magnitude of the plane velocity w.r.t. ground is

we know that the Vpg = Vpw + Vwg       .....................1

writing the component of the velocity that is

Vpw = (0 km/h î - 560 km/h j )

Vwg = (80 cos 45 km/h î + 80 sin 45 km/h j)

adding these

Vpg = (0+80 cos 45 km/h ) î  + ( -560 + 80 sin 45 km/h j)i

Vpg = (42.025 )  î  (-491.92 km/h)j

now we take magnitude

the magnitude of Vpg = \sqrt{(42.025^2+(-491.92)^2)} km/h

the magnitude of Vpg = 493.711 km/h

5 0
3 years ago
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