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kiruha [24]
3 years ago
10

Two forces with magnitudes of 6 pounds and 18 pounds are applied to an object. The magnitude of the resultant is 13 pounds. Find

the measurement of the angle between the resultant vector and the vector of the 18 pound force to the nearest whole degree.
Physics
1 answer:
Nikolay [14]3 years ago
6 0

Answer: the angle between the resultant vector and the vector of the 18 pound is 28°

Explanation:

given that data in the question; as its interpreted in the diagram below;

from the cosine rule, we know that;

a² = b² + c² - 2bc  

so

(13)² = (6)² + (18)² - (2 × 6 × 18 ) cos∅

169 = 36 + 324 - 216cos∅

169 = 360 - 216cos∅

216cos∅ = 360 - 169

216cos∅ = 191

cos∅ = 0.8842

∅ = cos⁻¹ ( 0.8842 )

∅ = 27.8° ≈ 28°  {nearest whole number}

Therefore the angle between the resultant vector and the vector of the 18 pound is 28°

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The sound level measured in a room by a person watching a movie on a home theater system varies from 40 dB during a quiet part t
UNO [17]

Answer:

\alpha=-3.01dB

Explanation:

From the question we are told that:

Sound level intensity

 \triangle I=40dB-80dB

Generally the equation for  intensity level  is mathematically given by

 \alpha=10log_{10}(I/I_x)dB

Where

 I= Intensity measured

 I_x=Threshold\ of\ audibility

 I_x= 10-12 W / m2

 \alpha= 10 log10 \frac{I_1}{I_x} - 10 log10 \frac{}I_2{I_x}

 \alpha= 10 log10 \frac{I_1}{I_2}

 \alpha=10 log10\frac{40}{80}

 \alpha=-3.01dB

7 0
3 years ago
A marble column of cross-sectional area 1.6 m^2 supports a mass of 26600 kg. The elastic modulus for marble is 5.0 times 10^10 N
vodka [1.7K]

Answer:

Δ L = 2.57 x 10⁻⁵ m

Explanation:

given,

cross sectional area = 1.6 m²

Mass of column = 26600 Kg

Elastic modulus, E = 5 x 10¹⁰ N/m²

height = 7.9 m

Weight of the column = 26600 x 9.8

                                    = 260680 N

we know,

Young's modulus=\dfrac{stress}{strain}

stress = \dfrac{P}{A}

           = \dfrac{260680}{1.6}

           = 162925

strain = \dfrac{\Delta L}{L}

now,

Y = \dfrac{stress}{strain}

\Delta L = \dfrac{162925}{Y}\times L

\Delta L = \dfrac{162925}{5 \times 10^10}\times 7.9

   Δ L = 2.57 x 10⁻⁵ m

The column is shortened by Δ L = 2.57 x 10⁻⁵ m

3 0
3 years ago
An aircraft flies at sea level at a speed of 220 m/s. What is the highest pressure that can be acting on the surface of the airc
goldenfox [79]

Answer:

An aircraft flying at sea level with a speed of 220 m/s, has a highest pressure of 29136.8 N/m²

Explanation:

Applying Bernoulli's equation, we determine the highest pressure on the aircraft.

P = \frac{1}{2} \rho V^2

where;

P is the highest pressure on the aircraft

\rho is the density of air = 1.204 kg/m³ at sea level temperature.

V is the velocity of the aircraft = 220 m/s

P = 0.5*1.204*(220)² = 29136.8 N/m²

Therefore, an aircraft flying at sea level with a speed of 220 m/s, has a highest pressure of 29136.8 N/m²

6 0
3 years ago
Read 2 more answers
3 Below, someone is trying to balance a plank with
belka [17]

Answer:

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b. The moment of the 6 N force is 12 N·m anticlockwise

Explanation:

In the figure, we have;

The distance from the point 'O', to the 6 N force = 2 m

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The position of the 4 N force relative to the point 'O' = To the right of 'O'

a. The moment of a force about a point, M = The force, F × The perpendicular distance of the force from the point

a. The moment of the 4 N force = 4 N × 4 m = 16 N·m clockwise

b. The moment of the 6 N force = 6 N × 2 m = 12 N·m anticlockwise.

8 0
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Aleksandr [31]

Answer:

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Explanation:

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8 0
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