3 years ago

A uniform rod of length L, mass M, is suspended by two thin strings. Which of the following statements is true

Physics

1 answer:

Fantom [35]3 years ago

6 0

Answer:

(d) not enough info

Explanation:

because it doesn't specify where the strings are attached

if it was the two ends of the rod then T1 would be equal to T2

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Select all the things the prefrontal cortex helps you do

stealth61 [152]

Understand future consequences, for tell the future, control urges, and delayed gratification

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3 years ago

3. Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 2

Nadusha1986 [10]

Explanation:

Work is the product of force and distance.

W = F×d

W = (22 N) × (16 m)

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What is the mass of an object traveling at 20m/s and having a momentum of 60kg⋅m/s?

vichka [17]

Answer:

m=3kg

Explanation:

Momentum=mass×speed

60[kg m/s]=m[kg]×20[m/s]

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m=3kg

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3 years ago

Read 2 more answers

a man can row about 4kmperhr in a still water.he rows the boat 2km up the stream and 2km back to his starting point in 2hr.how f

Nat2105 [25]

<u>Answer</u>:

The stream flowing at a speed of $2.828 \mathrm{km} / \mathrm{hr}$

<u>Explanation</u>:

Given:

Distance = 2km (both in upstream and downstream)

The speed in still water be x km/hr.

The speed in upstream = 4-x

Speed in downstream = 4+x

Solution:

We know that, Speed = distance/time

So, Time = distance/speed

Therefore,

$2=\left(\frac{2}{4-x}\right)+\left(\frac{2}{4+x}\right)$

$2=\frac{2(4+x)+2(4-x)}{(4-x)(4+x)}$

$2(4-x)(4+x)=2(4+x)+2(4-x)$

$2(4-x)(4+x)=2(4+x+4-x)$

By cancelling 2 on both sides,

$16-x^{2}=8$

$x^{2}=16-8=8$

$x=\sqrt{8}$

$x=2.828 \mathrm{km} / \mathrm{hr}$

Result:

Thus the speed of the stream is $2.828 \mathrm{km} / \mathrm{hr}$

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3 years ago

A mass of gas under constant pressure occupies a volume of 0.5 m3 at a temperature of 20°C. Using the formula for cubic expansio

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Without a change in pressure

V/T = V/T
Before change = after change - expansion

x = volume at m3

(0.5)/20 = x/45

.025 = x/45

.025 * 45 = x

1 = x

The volume of this gas is 1 m3.

Hope this helps :) also the gas expanded .5 of m3.

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3 years ago