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Gnom [1K]
3 years ago
9

Graph the solution set of: 2x - 4 ≤ 8 and x + 5 ≥ 7​

Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

Answer:

x ≤ 6 and x ≥ 2

Step-by-step explanation:

For now, we will start with doing each problem at a time. Here is your equation:

2x - 4 ≤ 8

First, you want to get the variable by itself. So, you add 4 to both sides. It will look like this:

2x - 4 ≤ 8

+ 4 + 4

The four being added on the left side cancels out, and you add 4 to 8. Now, it should look like this:

2x ≤ 12

Next, you want the x by itself. So, you would divide both sides by 2.

2x ≤ 12

/2 /2

2 divided by 2 cancels out, and 12 divided by 2 equals 6. Now, you have a final answer of:

x ≤ 6

But, you now have to do the other one!

Here is what you start off with:

x + 5 ≥ 7

First, you want the variable side by itself. So, you subtract 5 from both sides.

x + 5 ≥ 7

- 5 -5

Now, you have this:

x ≥ 2

Because the variable is already by itself, you don't need to do any more division and this is you final answer. Now put both answers you got together which equals:

x ≤ 6 and x ≥ 2

Tresset [83]3 years ago
4 0

First of all, we have to solve both inequalities: for the first one we have

2x-4\leq 8

Add 4 to both sides

2x\leq 12

Divide both sides by 2:

x\leq 6

For the second one we have

x+5\geq 7

Subtract 5 from both sides

x\geq 2

So, our solution set is composed by all numbers that are less than 6 (included) and more than 2 (included). Using all possible notations, we have

[2,6],\quad 2\leq x \leq 6,\quad \{x \in \mathbb{R}: 2\leq x \leq 6\}

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avanturin [10]

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Write our equation by putting the parts together, and we get:

y = -\frac{1}{2}x + 3

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3 years ago
The length of a rectangle is 2 units more than the width. The area of the rectangle is 63 units. What is the length, in units, o
Keith_Richards [23]

Answer:

Length = 9units

Width = 7units

Step-by-step explanation:

It is said that the length is 2units more than the width

Assume that the width is x, then the length will be 2 + x

ie

Width = x

Length = 2 + x

Area of the rectangle = 63units

Area of rectangle = l * b

l - length of the rectangle

b - width of the rectangle

A = l * b

63 = (2 + x) * x

63 = ( 2 + x) x

63 = 2x + x^2

Let's rearrange it

x^2 + 2x - 63 = 0

Let's find the factor of 63

A factor that can be multiplied to give -63 and that can be added to give +2

Let's use -7 and +9

x^2 - 7x + 9x - 63 = 0

Separate with brackets

( x^2 - 7x) + ( 9x - 63) = 0

x( x - 7) + 9(x - 7) = 0

( x + 9)(x - 7) = 0

( x + 9) = 0

( x - 7) = 0

x + 9 = 0

x = -9

x - 7 = 0

x = 7

Note: the length of a rectangle can not be negative

So therefore,

x = 7

Length = 2 + x

= 2 + 7

= 9units

Width = x

= 7units

7 0
3 years ago
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