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Maksim231197 [3]
2 years ago
11

By what number would you multiply to solve 4/5 t = 36

Mathematics
1 answer:
mihalych1998 [28]2 years ago
3 0

Answer:

45

Step-by-step explanation:

4/5 t = 36

Divide both sides by 4/5

4/5 / 4/5 t = 36/4/5

4/5 cancels 4/5

Also flip the divisor 4/5

t = 36x5 / 4

= 180/4

= 45

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For the function f(x)=x2-4, fins the value of f(x) when x=6
Snowcat [4.5K]

Answer:

32

Step-by-step explanation:

Substitute x = 6 into f(x), that is

f(6) = 6² - 4 = 36 - 4 = 32

5 0
3 years ago
For a school fundraiser, Mai will make school spirit bracelets. She will order bead wiring and alphabet beads to create the scho
Ket [755]

Answer: Total number of bracelet: 235

Step-by-step explanation:

Given:

Total budget= $1,500

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Per braclet beads = $5.30

Find:

Total number of bracelet

Computation:

Total number of bracelet = [1,500 - 250]

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8 0
2 years ago
A rectangular prism and its dimensions are shown in the diagram.
Sergeu [11.5K]

Answer:

148.2

Step-by-step explanation:

LA= PH

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8 0
2 years ago
Wich system of equations would have NO solution? (Answer correctly with work for branliest)
siniylev [52]

Answer:

A and D both equations don't have any solution

Step-by-step explanation:

y = 3x + 2

so y ≠ - 3x - 2

if 3x + y = 8

then 3x + y ≠ 9

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
1 year ago
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