The floor of a rectangular cage has a length 4 feet greater than its width, w. James

Mathematics

1 answer:

guajiro [1.7K]3 years ago

3 0

Answer:

x² + 8x + 12

Step-by-step explanation:

Area of a rectangle = length × width

Original dimensions:

Width = x

Length = x + 4

James will increase both dimensions of the floor by 2 feet

New dimensions:

Width = x + 2

Length = x + 4 + 2

= x + 6

Area of the new rectangle = length × width

= (x + 2) × (x + 6)

= x² + 6x + 2x + 12

= x² + 8x + 12

Equation which represents the

new area, N, of the floor of the cage = x² + 8x + 12

You might be interested in

Freeeeee points oh yah please thank me also for this what is 8+8

xenn [34]

Answer:

Step-by-step explanation:

8+8

5 0

4 years ago

Read 2 more answers

Use the distributive property to rewrite each problem so it only has two factors. Then solve. (44 times 3)+ (56 times 3)

Agata [3.3K]

132 + 168 = 300
Not sure if this is right.

8 0

4 years ago

Read 2 more answers

svetlana [45]

Answer:

$\large \boxed{\sf \text{The rate of the boat is } 53 \ km/h \text{, the rate of the current is }8\ km/h \ \ }$

Step-by-step explanation:

Hello, let's note v the rate of the boat and r the rate of the current. We can write the following

$\dfrac{135}{v-r}=3=\dfrac{183}{v+r}$

It means that

$135(v+r)=183(v-r)\\\\135 v + 135r=183v-183r\\\\\text{ *** We regroup the terms in v on the right and the ones in r to the left***}\\\\(135+183)r=(183-135)v\\\\318r=48v\\\\\text{ *** We divide by 48 both sides ***}\\\\\boxed{v = \dfrac{318}{48} \cdot r= \dfrac{159}{24} \cdot r}$