Use substitution.
y = 2 - x and y = 4x + 7 can become
2 - x = 4x + 7
Now solve for x
-5 = 5x
-1 = x
Now plug -1 for x in either equation.
y = 2 - x -> y = 2 - (-1) -> y = 3
y = 4x + 7 -> y = 4*-1 + 7 -> y = -4 + 7 -> y = 3
So C) is the correct answer.
Answer:
A-is farthest to the right on the number line
B-in the middle of the number line
C- farthest to the left on the number line
Step-by-explanation
If we have 3 random numbers we can conclude that a<c so we can say
A is farthest to the right
B in the middle
C: farthest to the left.
They are same side interior!! Not alternate, they’d be on opposite sides of the line
Since all four terms don't have a common factor we will group them in pairs with common factors.
6uv - 3v^3 + 4u - 2v^2
6uv + 4u - 3v^3 - 2v^2
Take out 2u from the first two terms and -v^2 from the last two terms. The goal is to have a common factor once we take out the GCF's.
2u( 3v + 2) - v^2(3v + 2)
Now we have two terms:
[2u(3v+2)] + [-v^2(3v+2)]
These two terms have a GCF of (3v + 2). Take that out:
(3v + 2)(2u - v^2)