What is the answer to this question, 2/5×6/7?

Mathematics

1 answer:

Jobisdone [24]3 years ago

6 0

Answer:

12/35

Step-by-step explanation:

Multiply both numerators and denominators.

2/5 * 6/7

=12/35

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Using distributive property what is the value of the expression for 2(-5 + 3)

Vladimir [108]

Answer:

-4

Step-by-step explanation:

According to the rules of the distributive property, you have to multiply the term outside of the parentheses with the terms inside the parentheses first.

1. 2(-5)=-10

2. 2(3)=6

The terms that we have are now -10 and 6. Add them together to get the final answer.

-10+6=-4

8 0

2 years ago

PLEASE HELP!!

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

8 0

3 years ago

If Ill m, solve for x.<br> (9x+2)<br> 119°<br> x =

Sav [38]

Answer:

x=13

Step-by-step explanation:

119-2=117

117÷9=13

9×13+2=119

3 0

2 years ago