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vekshin1
4 years ago
12

Rhonda had a piece of ribbon that was 5 feet 3 inches long. She removed a 5-inch piece to use in her art project. What is the le

ngth of the piece of ribbon now?
Mathematics
2 answers:
nikitadnepr [17]4 years ago
5 0

Answer:

4 feet 10 inches

soldier1979 [14.2K]4 years ago
5 0

It would be four feet and 10 inches

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In the diagram below, x is a whole number. what is the smallest possible value for x?
lesya692 [45]

Answer:

The smallest possible value for x is 9\ units

Step-by-step explanation:

we know that

The <u>Triangle Inequality Theorem</u>. states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

so

x+x>17\\2x>17\\x>8.5\ units

The value of x must be greater than  8.5\ units

so

If x must be a whole number

therefore

The smallest possible value for x is 9\ units

3 0
3 years ago
Given: F(x) = 2x2+ 1, G(x) = 2x - 1, H(x) = x F(3) + G(4) - 2H(5) = 16 26 34
Roman55 [17]

Answer:

  16

Step-by-step explanation:

Put the numbers where the variables are and evaluate:

  F(3) = 2(3)^2 +1 = 19

  G(4) = 2(4) -1 = 7

  H(5) = 5

Then the desired sum is ...

  F(3) +G(4) -2H(5) = 19 +7 -2(5) = 16

3 0
3 years ago
For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.
Flauer [41]

 

\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\

.

\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276

.

\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}    

 

 

8 0
3 years ago
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disa [49]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Need help! Will mark u brainliest for the right answer!
kirill115 [55]

To find the perimeter of this blue figure, add together the shown lengths of the six sides.  

The three measurements on the top have the LCD 4, so we combine 14 3/4, 4 2/4 and 8 2/4.  The sum is 26 7/4, or 27 3/4, or 27.75.

The three measurements on the bottom share the LCD 5, so we can immediately combine them, obtaining 32 8/5, or 33 3/5, or 33.60.

Combining 27.75 and 33.60 results in 61.35, or 61 35/100, or 61 7/20.

The perimeter of the given figure is 61 7/20.

3 0
3 years ago
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