All categories

2 years ago

Suppose point P (4,−9) is translated according to the rule (x,y) → ( x+3, y−2). What are the coordinates of P′? Explain.

Mathematics

1 answer:

larisa86 [58]2 years ago

5 0

Answer:

P'(7 , -11)

Step-by-step explanation:

what this tells us

(x,y) → ( x+3, y−2)

Is that the value of x of the new point is going to take (x + 3) with respect to the value of x of the other point.

Is that the value of y of the new point is going to take (y - 2) with respect to the value of y of the other point.

P (4,−9)

x = 4

y = -9

P'( x+3, y−2)

x + 3 =

4 + 3 = 7

y - 2 =

-9 - 2 = -11

P'(7 , -11)

You might be interested in

for sale, a store decrease it's price on all items by 25%. An item that cost $ 120 before the sale now costs $120 - 0.25 ( $ 120

zheka24 [161]

It would then cost $90 because 25% of $120 is $30

3 0

3 years ago

Task: Multiplying and Dividing Expressions

koban [17]

Najsjsiskekasizjnsdkdkdkx

3 0

3 years ago

A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)

stiks02 [169]

Answer: 82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB $=\sqrt{(9+1)^2+(-1-7)^2}$ units [By distance formula : $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ ]

$=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41}$ units

Width = BC = $\sqrt{(-1+5)^2+(7-2)^2}$ units

$=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}$

Area = length x width

= $2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}$

Hence, the area of the rectangle is 82 sq. units .

7 0

3 years ago

X^2 +18 =15 could anyone help me with this?

stiv31 [10]

Answer:

x = i√3, -i√3

Step-by-step explanation:

Simply take the root of both sides, then solve.

8 0

3 years ago

Read 2 more answers

Help please!!!!!!!!!

devlian [24]

Answer:

YOU not smartYOU DONT KNOW THIS HA HA NOT HELPING YOU BOT.

Step-by-step explanation:

4 0

2 years ago