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Mandarinka [93]

3 years ago

9

Can anyone help me please? I really need it.

1 answer:

Artemon [7]3 years ago

6 0

First you set f(x) and h(x) equal to each other. So 1/x+1=2x+3. Next, you multiply each side by 1 to cancel out the fraction. So now the answer is x+1=2x+3. Now subtract 1 from each side. X=2x+2. Subtract 2x from each side now. -2x=2. Divide by -2x and get the answer x= -1

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Is 3 a divisor of 51?

Mariulka [41]

Answer:
Yes

Step by step explanation

5 0

3 years ago

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A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of

Gwar [14]

$\bold{\huge{\underline{ Solution}}}$

<h3><u>Given </u><u>:</u><u>-</u></h3>

A marker in the center of the fairway is 150 yards away from the centre of the green
While standing on the marker and facing the green, the golfer turns 100° towards his ball
Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

Distance between marker and centre of green is 150 yards
<u>That </u><u>is</u><u>, </u>Height = 150 yards
For facing the green , The golfer turns 100° towards his ball
<u>That </u><u>is</u><u>, </u>Angle = 100°
The golfer peces off 30 yards to his ball
<u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

$\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}$

Here, a = perpendicular height
b = base
c = hypotenuse
cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

$\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}$

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}$

$\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}$

$\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}$

$\sf{ x^{2} = 22500 + 900 + 156.6}$

$\sf{ x^{2} = 23556.6}$

$\bold{ x = 153.48\: yards }$

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0

3 years ago

−3/4+(1/10÷2/5) PLZ HELP

Rzqust [24]

−3/4+(1/10÷2/5)

parenthesis first

1/10 divided by 2/5

copy dot flip

1/10 * 5/2

5/20

1/4

−3/4+(1/10÷2/5)

-3/4 + 1/4

-2/4

divide top and bottom by 2

-1/2

8 0

3 years ago

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CAN SOMEONE HELP ME IN THIS QUESTION?

svetoff [14.1K]

I
I'm pretty sure it is B.

8 0

4 years ago

kondaur [170]

Answer:

70kilometers

Step-by-step explanation:

first we must find how much one half of a centimeter is

well, its easy, theres already a half for the distance, and the representation is an even number, so cut it in half.

20-10 is 10

and now the multiplication

20x3=60

60+10=70

70 kilometers

3 0

3 years ago