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3 years ago

PLEASE HELP ITS DUE IN 5 MINS WILL MARK THE BRAINLEST PLEASE HURRY ITS DUE

Mathematics

1 answer:

Sidana [21]3 years ago

3 0

Answer:

I think B is true

Step-by-step explanation:

No timee

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Can someone help me?

Lapatulllka [165]

Answer:

idk

Step-by-step explanation:

we are nt on that yet

5 0

3 years ago

Whats the square root of 1/5 minus the square root of 5

I am Lyosha [343]

You have to simplify the 1/5 first.
Then simplify the square root of 1 to equal 1
Then rationalize the denominator
Then simplify

8 0

3 years ago

Please help.

m_a_m_a [10]

Answer:

26.2

Step-by-step explanation:

PQ/QR = 8/16 = 0.5

tan(26.6) = 0.5

7 0

3 years ago

A Square was altered so that one side is increased by 9 inches in the other side is decreased by 2 inches.The area of the result

LekaFEV [45]

Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.

The area of this rectangle is (s+9)(s-2) = 60 in^2.

This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:

s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.

4 0

3 years ago

A bag contains 6 green counters, 4 blue counters and 2 red counters. Two counters are drawn from the bag at random without repla

Svetach [21]

Answer:

24.24%

Step-by-step explanation:

In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12

Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.

$\frac{4}{12} * \frac{8}{11} = \frac{32}{132}$ or 0.2424 or 24.24%

8 0

3 years ago