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4 years ago

9

Dustin says that 8 • -1 = 8 is a counter example that shows the following conditional statement is false. Is Dustin correct? Exp

lain. If two integers are multiplied. Then the product is greater than both integers.

1 answer:

Allisa [31]4 years ago

5 0

dustin is correct because 8*-1 is 8 beacse its diffent and u soppse to sub

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1 1/2 as a fraction

Alik [6]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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3 years ago

Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

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$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

4 0

3 years ago

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What’s the translation from the graph y=6x^2 to the graph y=6(x+1)^2

Leno4ka [110]

For this case, the main function is given by:

$y = 6x ^ 2$

We can apply the following transformation:

Horizontal displacements:

Assume h> 0:

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For h = 1 we have:

$y = 6 (x + 1) ^ 2$

Answer:

the graph y=6(x+1)^2 is the graph y=6x^2 moved 1 unit to the left.

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3 years ago

Which statement can be used to prove that a given parallelogram is a rectangle? The diagonals of the parallelogram are perpendic

liubo4ka [24]

The answer in this question is B The diagonals of the parallelogram are congruent because that's only possible for right angle quadrilaterals. We can say that the diagonals of the parallelogram are congruent. The diagonals of this figures have the same size and shape.

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3 years ago

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