Alright so I'm coming up with this on the fly; you have the first six letters (a,b,c,d,e,f) and 0-9 and your ten numbers. calculate the amount of possible combinations for the letters by simply writing them down.
ab, ac, ad, ae, a f- five
bc, bd , be, bf- four
cd, ce, cf- three
de, df- two
ef,- one.
adding these all together gets a total of 15 for the letters. now the numbers
01, 02, 03, 04, 05, 06, 07, 08, 09- nine
12, 13, 14, 15, 16, 17, 18, 19- eight
23, 24, 25, 26, 27, 28, 29- seven
34, 35, 36, 37, 38, 39- six
45, 46, 47, 48, 49- five
56, 57, 58, 59- four
67, 68, 69- three
78, 79- two
89- one
added together with a total of 45 combinations.
alright so, 45 different number combinations and 15 letter combinations. multiplying 15 by 45 should tell you the total possible combinations for a two letter and two number serial-number
5w+12=67
-12 -12
5w=55
w=11
first, subtract 12 from both sides. second, divide 5 on both sides
To solve this problem you must apply the proccedure shown below:
1. You have that the the <span>archway is modeled by the equation y=-2x^2+8x and the angle mentioned in the problem is defined by the equation x−2.23y+10.34=0.
</span>
2. Therefore, you must susbtitute y=-2x^2+8x into x−2.23y+10.34=0, as below:
x−2.23(-2x^2+8x)+10.34=0
3. When you apply the distributive property, you obtain:
x−2.23(-2x^2+8x)+10.34=0
x+4.46x^2-17.84x+10.34=0
4.46x^2-16.84x+10.34=0
4. When you solve the quadratic equation, you obtain:
x=3 units
Therefore, the answer is the option D: D. 3 units.
Answer:
9
Step-by-step explanation: A^2+B^2=C^2
