Question

A particular baseball player has a batting average (number of hits/number of times at bat) of 0.364. What is the probability that he will not get a hit at his next at bat?
P(not a hit) = 1.364
P(not a hit) = 0.626
P(not a hit) = 0.636
P(not a hit) = 0.364

Answer 1

The correct answer is option (c) P(not a hit) = 0.636

The batting average of the baseball player = $\frac{number of hits}{number of times at bat}$ = 0.364

Now, the probability of occurrence of any event is say, P, the probability of not occurrence of the event is given as =  1 - P

Therefore, the probability that he will not get a hit at his next at bat = 1- 0.364 = 0.636