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anyanavicka [17]
3 years ago
13

A particular baseball player has a batting average (number of hits/number of times at bat) of 0.364. What is the probability tha

t he will not get a hit at his next at bat?
P(not a hit) = 1.364
P(not a hit) = 0.626
P(not a hit) = 0.636
P(not a hit) = 0.364
Mathematics
1 answer:
MAXImum [283]3 years ago
6 0
The correct answer is option (c) <span>P(not a hit) = 0.636

</span>The batting average of the baseball player = \frac{number of hits}{number of times at bat} = 0.364

Now, the probability of occurrence of any event is say, P, the probability of not occurrence of the event is given as =  1 - P

Therefore, <span>the probability that he will not get a hit at his next at bat = 1- 0.364 = 0.636</span>
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Required

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h = \frac{3 * 36}{4\sqrt 3}

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V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

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