Point C is located at (1, 2) and point D is located at (−4, −2). Find the x value for the point that is 1\4 the distance from po
1 answer:
The easiest way to do this is to realize this is a <em>weighted average</em> of the two points. (A weighted average is a linear combination where the coefficients add to one.)
(x,y) = (1-t)C + tD
where t is a real parameter. When t=0 we're at point C, when t=1 we're at point D. We're interested in t=1/4,
(x,y)= (3/4) C + (1/4) D
We're only asked for the x coordinate:
x = (3/4) (1) + (1/4) (-4) = 3/4 - 1 = - 1/4
Answer:
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9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
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If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.
