Point C is located at (1, 2) and point D is located at (−4, −2). Find the x value for the point that is 1\4 the distance from po
1 answer:
The easiest way to do this is to realize this is a <em>weighted average</em> of the two points. (A weighted average is a linear combination where the coefficients add to one.)
(x,y) = (1-t)C + tD
where t is a real parameter. When t=0 we're at point C, when t=1 we're at point D. We're interested in t=1/4,
(x,y)= (3/4) C + (1/4) D
We're only asked for the x coordinate:
x = (3/4) (1) + (1/4) (-4) = 3/4 - 1 = - 1/4
Answer:
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Answer:
It takes 2.8 seconds for the ball to fall 215 ft.
Step-by-step explanation:
We are given a position function s(t) where s stands for the number of feet the ball has fallen, so we have to replace s with the given value of 215 ft and solve for the time t.
Setting up the equation.
The motion equation is given by
We can replace there s = 215 ft to get
Solving for the time t.
From the previous equation we can move all terms in one side to get
At this point we can solve for t using quadratic formula.
where a, b and c are the coefficients of the quadratic equation
So we get
Replacing on the quadratic formula we get
Using a calculator we get
Physically speaking the only result that makes sense is to move forward in time that give us t = 2.8 seconds.
We can conclude that it takes 2.8 seconds for the ball to fall 215 ft.