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skad [1K]
3 years ago
15

Help again idk how to do this

Mathematics
2 answers:
aalyn [17]3 years ago
7 0
The answer is A.

This is because the 5 to the power of 3 is in parentheses, anything in parentheses is multiplied my whatever is outside the parentheses. Please let me know if this is correct or incorrect. Thank you!
creativ13 [48]3 years ago
5 0

Answer:

it's,

( {5}^{3} ) ^{ - 4}  \\

Step-by-step explanation:

( {5}^{3} ) ^{ - 4}  \\  =  {5}^{ - 12}

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Write two equivalent ratios 3to5??
vesna_86 [32]

Answer:

3 : 5

6 : 10

9 : 15

12 : 20

15 : 25

7 0
3 years ago
Q. Find the measure of QR
Andreas93 [3]

Answer: 22

Step-by-step explanation:

Since U is the midpoint of P and R, and S is the midpoint of P and Q, SU must be a midsegment.

By the midsegment theorem, SU is 1/2 the value of QR. Therefore QW = SU*2 = 11*2 = 22.

8 0
3 years ago
Which statement describes the inverse of m(x) = x^2 – 17x?
DochEvi [55]

Given:

The function is

m(x)=x^2-17x

To find:

The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

Substitute m(x)=y.

y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

7 0
3 years ago
Two non-common sides of adjacent supplementary angles form a _____ angle.
mel-nik [20]

Answer:

C. straight

Step-by-step explanation:

 A Linear Pair is two adjacent angles whose non-common sides form opposite rays.

If two angles form a linear pair, the angles are supplementary.

A linear pair forms a straight angle which contains 180º, so you have 2 angles whose measures add to 180, which means they are supplementary.

In the figure given in attachment, AB and BC are two non common sides of ∠ABD and ∠DBC.

∠1 and ∠2 form a linear pair.

The line through points A, B and C is a straight line.

∠1 and ∠2 are supplementary.

Thus two non-common sides of adjacent supplementary angles form a <u>straight</u> angle.

8 0
3 years ago
How many ways can 4 pizza toppings be chosen from 12 available toppings
Arisa [49]

Answer:

There are 495 different ways to choose 4 pizza toppings from 12.

Step-by-step explanation:

12!/8!4! = 12*11*10*9/(4*3*2) = 11*9*5 = 495

5 0
3 years ago
Read 2 more answers
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