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Ierofanga [76]
3 years ago
7

(8b2+6b-1) (8b2-8b+7)

Mathematics
1 answer:
suter [353]3 years ago
6 0
<span>=(<span><span><span>8<span>b2</span></span>+<span>6b</span></span>+<span>−1</span></span>)</span><span>(<span><span><span>8<span>b2</span></span>+<span>−<span>8b</span></span></span>+7</span><span>)
</span></span>=<span>(8b2)(8b2)+(8b2)(−8b)+(8b2)(7)+(6b)(8b2)+(6b)(−8b)+(6b)(7)+(−1)(8b2)+(−1)(−8b)+(−1)(7)
</span>=<span>64b4−64b3+56b2+48b3−48b2+42b−8b2+8b−7</span>
Answer:
=<span>64b4−16b3+50b−7</span>
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kondaur [170]

Answer:

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8 0
2 years ago
X-3y=2 what is the slope
Brums [2.3K]
1/3 is the slope.
x-3y=2
-3y=-x+2
y=(1/3)x+2/3
3 0
3 years ago
(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard
AveGali [126]

Answer:  

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.95=0.05

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: t_{n-1,\alpha/2}=t_{7,0.025}=2.365

Sample mean : \overline{x}=24.8\text{ hours}

Standard deviation : \sigma=3.2\text{ hours}

The confidence interval for population means is given by :-

\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}

24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)

Hence, the 95% confidence interval, assuming the times are normally distributed.=  (22.12, 27.48)

6 0
3 years ago
Jonah studied for 3 hours longer than sierra. he also studied for 3 times as many hours as william. these relationships are show
Butoxors [25]

Answer:

i dont know Sierra studied for 7 and William studied for 3

Step-by-step explanation:

4 0
3 years ago
Which is the equation in slope intercept form for the line that passes through (-3,3) and is parallel to 3x + y= 7?
Helga [31]

Answer: B

See how I get

3 0
3 years ago
Read 2 more answers
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