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Ierofanga [76]
3 years ago
7

(8b2+6b-1) (8b2-8b+7)

Mathematics
1 answer:
suter [353]3 years ago
6 0
<span>=(<span><span><span>8<span>b2</span></span>+<span>6b</span></span>+<span>−1</span></span>)</span><span>(<span><span><span>8<span>b2</span></span>+<span>−<span>8b</span></span></span>+7</span><span>)
</span></span>=<span>(8b2)(8b2)+(8b2)(−8b)+(8b2)(7)+(6b)(8b2)+(6b)(−8b)+(6b)(7)+(−1)(8b2)+(−1)(−8b)+(−1)(7)
</span>=<span>64b4−64b3+56b2+48b3−48b2+42b−8b2+8b−7</span>
Answer:
=<span>64b4−16b3+50b−7</span>
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If B is x+y=16, then x=5 and y=11

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<h3>Answer options:</h3>

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