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Ierofanga [76]
3 years ago
7

(8b2+6b-1) (8b2-8b+7)

Mathematics
1 answer:
suter [353]3 years ago
6 0
<span>=(<span><span><span>8<span>b2</span></span>+<span>6b</span></span>+<span>−1</span></span>)</span><span>(<span><span><span>8<span>b2</span></span>+<span>−<span>8b</span></span></span>+7</span><span>)
</span></span>=<span>(8b2)(8b2)+(8b2)(−8b)+(8b2)(7)+(6b)(8b2)+(6b)(−8b)+(6b)(7)+(−1)(8b2)+(−1)(−8b)+(−1)(7)
</span>=<span>64b4−64b3+56b2+48b3−48b2+42b−8b2+8b−7</span>
Answer:
=<span>64b4−16b3+50b−7</span>
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The value (in cents) of the change in a purse that contains twice as many nickels as pennies, five more dimes than nickels, and
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Value of the pursue in cents: 131p+175

Step-by-step explanation:

Let's call:

p = number of pennies

The problem tells us that the pursue contains twice as many nickels as pennies, so the number of nickels is

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Also, the pursue contains five more dimes than nickels, so the number of dimes is

d=n+5=2p+5

And finally, the pursue contains as many quarters as dimes and nickels combained, so the number of quarters is

q=d+n=(2p+5)+2p=4p+5

The value of each type of coin is:

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Nickel: 5 cents

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So, the total value of the pursue in cents is:

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So, this is the value of the change in the pursue in cents.

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brainly.com/question/7014769

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