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dsp73
3 years ago
14

Write an equation of a line parallel to line GH below in slope-intercept form that passes through the point (−5, 6).

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0
<h2>Answer:</h2>

The equation of a line parallel to line GH in slope-intercept form that passes through the point (−5, 6) is:

                         y=x+11

<h2>Step-by-step explanation:</h2>

The line GH passes through:

(-2,2) and (2,6)

The slope of a given line GH is given by:

Slope(m)=\dfrac{6-2}{2-(-2)}\\\\\\Slope(m)=\dfrac{4}{4}\\\\\\i.e.\\\\\\Slope(m)=1

We know that if a line is parallel to a given line than both have the same slope.

i.e. the slope of second line is: 1

Also, we know that a equation of a line with given slope "m" and passing through point (a,b) is given by:

y-b=m(x-a)

Here we have m=1

and (a,b)=(-5,6)

and hence the equation of parallel line is:

y-6=1(x-(-5))\\\\\\i.e.\\\\\\y-6=x+5\\\\\\i.e.\\\\\\y=x+5+6\\\\\\i.e.\\\\\\y=x+11

                Hence, the equation is:

                     y=x+11

icang [17]3 years ago
6 0
The slope of GH is 1, so any line parallel to GH will have the same slope.

Since this other line passes through (-5,6), you can use the point-slope formula:

y-6=1(x-(-5))\implies y-6=x+5\implies y=x+11

so you are correct.
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svp [43]

Answer:

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Explanation:

<em>If he makes $1 for each order and he filled out 385 orders, then why can't we say he made $385?</em>

Because of this statement rights here:

"...and gets paid $1 for each order he fills out plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20."

So we need to find out if any of the 3 weeks has an average of 20+ orders per day.

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<h2>plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20. </h2>

if any average orders per day is > 20 in any week

bonus profit = $1.25x

<h2>The ratio of the number of orders he processed during the first week to the number of orders he processed during the second week is 3:2, </h2>

first week     second week

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<h2>while the the ratio that compares the number of orders he filled out during the first and the third weeks is 4 to 5 respectively. </h2>

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           4a : 5a

<h2>What amount of money will David make at the end of three weeks if the total number of orders he filled out was 385?</h2>

sum of all ratios of a = 385

So we have

3a : <u>2a</u> (first week to <u>second week</u>)

4a : <em>5a </em>(first week to <em>third week</em>)

Notice how the first two numbers are both from the first week. Let's use the Least Common Multiple to make them equal while still keeping ratios.

LCM of 3 and 4: 12 = 3 * 4

12a : <u>8a</u> ( times 4 )

12a : <em>15a</em> ( times 3 )

Now that we have the same value, we can create a big ratio

first week <u>second week</u> <em>third week</em>

   12a     :        <u>8a</u>          :      <em>15a</em>

we know that these ratios will all equal 385. Since ratios are equal no matter how big we make them, we can say that

12a + <u>8</u>a + <em>15</em>a = 385 (a is a variable to scale up the ratio)

which is the same as

(12 + <u>8</u> + <em>15</em>) * a = 385

(<em><u>35</u></em>) * a = 385

35a = 385

if we solve for a by dividing 35 on both sides we get

a = 11

This gives us how much to multiply the RATIO by to get the ACTUAL NUMBER of orders completed. Let's plug 11 for 'a' and see what happens.

12a + <u>8</u>a + <em>15</em>a = 385

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<u>220</u> + <em>165</em> = 385

<em><u>385</u></em> = 385

Bingo! All the math works out. So, looking back at the verryyy top of this problem, the reason why it wasn't as easy as $385 was because of the bonus.

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165 orders / 7 days (7 days in a week) = 23.57 orders per day

Is this greater than 20 orders per day?

YES!

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So instead of using

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bonus profit = $1.25 * 385

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If necessary, round your answer to the nearest dollar.

So for the very end, all we have to do is round it to the nearest dollar.

$481.25 rounds to $481.

And we're done!

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