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Anni [7]
3 years ago
13

Help me!!! Please and thank you!!!

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

Third option is correct: 1 / (t+4)^2

Step-by-step explanation:

This equation can be written as the following:

(t+3)/(t+4)*(1/t^2+7t+12)

We know this because of the division of fractions. For example:

(1/y)/(1/x) = (1/y)*(x/1)

Now that we know this, we can advance.

Now we have to try to factor (t^2+7t+12)

We can make this into (t+3)(t+4)

Ah! Perfect! There is a t+3 in the denominator of the first fraction!

We can now cancel these out.

Now our equation looks like this:

(1 / t+4) * (1 / t+4)

This can also be written as 1^2 / (t+4)^2 = 1 / (t+4) ^2

So the correct option is the third one.

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PLZZZZZZZZZ HELP ASAPPPPPPP
Tamiku [17]

Answer:

the answer is 28 if you multiply if not 30

3 0
2 years ago
The owner of an auto repair shop studied the waiting times for customers who arrive at the shop for an oil change. The following
labwork [276]

Answer:

(d)0.6

Step-by-step explanation:

(a)Frequency Distribution

\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Frequency\\-----------&--\\0-4&4\\5-9&8\\10-14&5\\15-19&2\\20-24&1\\--&--\\Total&20\end{array}\right|

(b)The relative frequency distribution.

\left|\begin{array}{c|c}$Waiting Time(in Minutes)&$Relative Frequency\\-----------&--\\0-4&4/20=0.2\\5-9&8/20=0.4\\10-14&5/20=0.25\\15-19&2/20=0.1\\20-24&1/20=0.05\\--&--\\Total&1\end{array}\right|

(c)The cumulative frequency distribution.

\left|\begin{array}{c|c|c}$Waiting Time(in Minutes)&$Frequency&$Cumulative Frequency\\-----------&--&---\\0-4&4&4\\5-9&8&12\\10-14&5&17\\15-19&2&19\\20-24&1&20\\--&--&--\\Total&20\end{array}\right|

(d)The proportion of customers needing an oil change who wait 9 minutes or less.

Proportion of customers needing an oil change who wait 9 minutes or less.

=\dfrac{12}{20} \\\\=0.6

5 0
3 years ago
Please include work!
geniusboy [140]

Answer:

x = ± 4

y = - 2

Step-by-step explanation:

y = 0.5x² - 10 ------------------------(I)

y = -x² + 14   ------------------------(II)

Substitute the y value in equation (II)

    0.5x² - 10  = -x² + 14           {Add x² to both sides}            

0.5x² + x² -10 = 14                  {combine like terms}

       1.5x² - 10 = 14                   {Add 10 to both sides}

               1.5x² = 14 + 10

                1.5x² = 24         {Divide both sides by 1.5}

               1.5x²/1.5 = 24/1.5

                       x² = 16

                      x = ±4

Substitute x = 4 in (I)

y = 0.5 * 4² - 10

 = 0.5*16 - 10

 = 8- 10

y = -2

Substitute x = -4 in (I)

y = 0.5 * (-4)² - 10

 = 0.5*16 - 10

 = 8- 10

y = -2

5 0
3 years ago
Find S5 for a geometric series for which a1=81 and r=1/9.
Minchanka [31]

ANSWER

S_5=91\frac{10}{81}




EXPLANATION


The sum of the first n terms of a geometric sequence is given by;


S_n=\frac{a_1(1-r^n)}{1-r} ,-1


Where n, is the number of terms and a_1 is the first term.


When n=5, we have a_1=81, we get;


S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}


S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}


S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}




S_5=\frac{7381}{81}


S_5=91\frac{10}{81}




6 0
3 years ago
PLEASE HELP!
Fed [463]

Not sure for (b)

Step-by-step explanation:

(a)55+80+x=180 (angles inside the triangle)

135+×=+180

x=180-135

x=45

8 0
2 years ago
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