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4 years ago

Which of the following symbols results in a true number sentence when placed in the blank?

1 answer:

5 0

The term is used as means of asking students to write down equations using simple mathematical symbols (numerals, the four basic mathematical operators, equality symbol)[5]. Sometimes boxes or shapes are used to indicate unknown values. As such number sentences are used to introduce students to notions of structure and algebra prior to a more formal treatment of these concepts.

A number sentence without unknowns is equivalent to a logical proposition expressed using the notation of arithmetic.

[edit] Examples
A valid number sentence that is true: 3 + 7 = 10.

A valid number sentence that is false: 7 + 9 = 17.

A valid number sentence using a 'less than' symbol: 3 + 6 < 10.

An example from a lesson plan:

Some students will use a direct computational approach. They will carry out the addition 26 + 39 = 65, put 65 = 23 + □, and then find that □ = 42.[6] (wikipedia)

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Answer:

Case n =5

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894$

Case n =15

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549$

Case n = 40

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530$

P value

Case n =5

$p_v =P(z$

Case n =15

$p_v =P(z$

Case n =40

$p_v =P(z$

Step-by-step explanation:

Data given and notation

$\bar X=4.8$ represent the sample mean

$\sigma=0.5$ represent the population standard deviation

$n$ sample size

$\mu_o =5$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 5, the system of hypothesis would be:

Null hypothesis: $\mu \geq 5$

Alternative hypothesis: $\mu < 5$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

Case n =5

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894$

Case n =15

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549$

Case n = 40

$z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530$

P-value

Since is a left tailed test the p value would be:

Case n =5

$p_v =P(z$