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jekas [21]
3 years ago
8

Which of the following sets of side lengths would not form a triangle?

Mathematics
1 answer:
Drupady [299]3 years ago
8 0

The answer is A.

29 + 39 < 69.

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Find the midpoint of the segment with the following endpoints. (10, 7) and (5, 4)
KatRina [158]

Answer:

\frac{15}{2} , \frac{11}{2}

Step-by-step explanation:-

To find the midpoint, the equation we use is:-

\frac{x1 +x2}{2} , \frac{y1 + y2}{2}

x1 = 10

x2 = 5

y1 = 7

y2 = 4

Substituting the values in the equation, we get:-

\frac{10+5}{2} , \frac{7+4}{2}

Coordinates of the midpoint---> \frac{15}{2} , \frac{11}{2}

8 0
3 years ago
I HAVE 5 MIN TO TURN THIS IN!!!! PLEASE HELP ME!!!<br> IT'S IN THE IMAGE BELOW
Mariulka [41]

Answer:

<h3>a.  x = 8 years</h3><h3>b.  52,000</h3><h3 />

Step-by-step explanation:

company A = 28,000 + 3,000 (x)

company B = 36,000 + 2,000 (x)

where x = no. of years.

  • <u>company A = company B</u>

28,000 + 3,000 (x) = 36,000 + 2000 (x)

3,000 (x) - 2,000 (x) = 36,000 - 28,000

1,000 (x) = 8,000

x = <u>8,000</u>

     1,000

<h3>x = 8 years</h3>

  • plugin value of x = 8 into company A and B

company A = 28,000 + 3,000 (8)

<h3>company A = 52,000</h3>

company B = 36,000 + 2,000 (8)

<h3>company B = 52,000</h3>
5 0
3 years ago
Jim and his dad are building a rectangular flower bed. They have a total of 35 feet of landscaping timber to use, and they want
Mama L [17]
The perimeter is 35.  If we were to change the width, which is one of the dimensions of the flower bed, The perimeter will change.  This means that perimeter will no longer be 35.  So in order to keep the perimeter as it is, if we change one dimension, we must also change the other. Let's solve for the length, using the formula to see how much the length changes from. p = 2l + 2w 35 = 2l + 2(15) 35 = 2l + 30 5 = 2l 2.5 = l  We must increase the length from 2.5 feet.  This is because decreasing one dimension will decrease the perimeter.  But if we increase the other dimension as well, it will restore the perimeter to where is was initially.
4 0
3 years ago
Read 2 more answers
Are the given ratios equivalent Explan why or why not 3 : 5 12 : 20​
sasho [114]
Yes you take 3 times 4 and receive 12 and 5 times 4 and receive 20
4 0
2 years ago
Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the
sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let y(t) be the depth of water in the barrel at time t,  where y is measured in inches and t in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

                                                 \frac{dy}{dt}=-k\sqrt{y}

where k is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by \frac{1}{\sqrt{y}}

\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k

Multiply by dt

\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt

Take integral

\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt

Integrate

2\sqrt{y}=-kt+C

Isolate y

y(t)=(\frac{C}{2} -\frac{k}{2}t)^2

We know that the water level starts at 36, this means y(0)=36. We use this information to find the value of C.

36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12

y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2

At t = 1, y = 34

34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}

So our formula for the depth of water in the barrel is

y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\

To find the time, t, at which all the water leaks out of the barrel, we solve the equation

\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0
4 years ago
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