Answer:49 sec
Step-by-step explanation:
Given
Maximum speed to reach is 183.58 mi/h
Length of course is 5 mi
acceleration rate is defined by 60mi/h in 4 sec
therefore acceleration(a)
To reach a speed of 183.58mi/h with an acceleration of
Using equation of motion
v=u+at
t=0.00339 hours
t=12.23 s reach maximum speed
To complete course it takes
t=0.01360 hour
or
Answer:
x^2 - 12x..............................
Answer: t = 6 s
Step-by-step explanation:
When Rose hit the water, the height of the jump is 0, so: h(t) = 0.
Resolving it, we have:
-16t² + 16t + 480 = 0
To simplify the second degree equation, divided it by 16:
-t² + t + 30 = 0
Now, solve the equation using Bhaskara:
Δ = 1² - 4. (-1) . 30
Δ = 1 + 120
Δ = 121
t =
t₁ = = - 5
t₂ = = 6
Since time can be negative, it took t = 6s for Rose to hit the water.
Answer:
Step-by-step explanation:
Each 90° clockwise turn takes a point (x,y) and transforms it to (y,-x). For a 180° turn you would do this process twice in a row; for a 270° turn, three times in a row.