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babymother [125]
2 years ago
13

When the sum of a number, n, and 6 is divided by 4 the

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
6 0

Answer:

n = 14

Step-by-step explanation:

(n + 6)4 = 5

1. multiply by 4

n + 6 = 20

2. substract 6

n = 14

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What is 31/4 in simplest form
KATRIN_1 [288]
In fraction form 31/4 is simplified. In decimal form 7.75 would be your answer.
5 0
3 years ago
Read 2 more answers
Turn 1 1/5 to improper fraction
Alex17521 [72]

Answer:

<h2><em><u>6/5</u></em></h2><h2></h2>

Explanation:

Step 1

Multiply the denominator by the whole number

5 × 1 = 5

Step 2

Add the answer from Step 1 to the numerator

5 + 1 = 6

Step 3

Write answer from Step 2 over the denominator

<h2><u>6/5</u></h2><h2><u></u></h2><h2><u>I hope this answer helps you out! Brainliest would be appreciated.</u></h2>
4 0
3 years ago
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
2 years ago
What is the square root of 9800 in simplest radical form?
Mumz [18]
The square root of 9800=

= 70 * square root of 2


4 0
3 years ago
Trigonometry that’s due in one hour :(
expeople1 [14]

Answer:

(a)  \theta=\tan^{-1}(-0.890)

\implies \theta=-41.66908262 \pm 180 \textdegree n

\implies \theta=138.3309174..., 318.3309174...

\implies \theta=138\textdegree, 318\textdegree

(b)  \theta=\cos^{-1}\left(\dfrac{\sqrt{3} }{2}\right)

\implies \theta=30 \textdegree \pm360 \textdegree n, 330 \textdegree \pm360 \textdegree n

\implies \theta=30 \textdegree , 330 \textdegree

(c)  \theta=\sin^{-1}\left(\dfrac{1 }{2}\right)

\implies \theta=30 \textdegree \pm360 \textdegree n, 150 \textdegree \pm360 \textdegree n

\implies \theta=30 \textdegree , 150 \textdegree

3 0
2 years ago
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