To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
Hello :
<span> the equation of the circle is (x-a)²+(y-b)² = r²
A(a;b) center r : </span><span>radius
</span>in this exercice : (x+3)²+y²=25
Answer:
Step-by-step explanation:
There is no fractional or decimal part. And no negatives. 1/3 = 0.33333333 with 3 keep repeating. If you want to round it to the nearest whole number, it is 0
Lower extreme- 8
Lower quartile- 20
Median- 30
Upper quartile- 35
Upper extreme- 42
Hope this helps!
So the formula to workout the area of a rectangle is height X width
so 11/3 x 5/8
which is 55/24 ft if they want a mixed number then... 2 
hope this helps
