Try this option:
1. if 8*x²+b*x+3=8*x²+p*x+q*x+3, then ⇒ b=p+q.
2. p*q = max_value (b²/2), if p=q=0.5*b, and p*q→-oo, if p>0 and q<0 or p>0 q<0.
3. example:
given 8x²+10x+3, the student rewrites it as a) 8x²+5x+5x+3 (5*5=25-max value); b) 8x²+0.01x+9.99x+3 (9.99*0.01=0.0999→0); c) 8x²-20x+30x+3 (p*q=-600).
answer: (-oo;0.5b²)
Answer:
y = 3/4 x - 5
Step-by-step explanation:
The slopes of perpendicular lines are negative reciprocals. We find the slope of the given line. Then we can find the slope of the reciprocal.
4x + 3y = -6
Solve for y.
3y = -4x - 6
y = -4/3 x - 2
The slope of the original line is -4/3.
The slope of the perpendicular is 3/4.
Now we need to find the equation of line with slope 3/4 that contains point (4, -2).
y = mx + b
-2 = (3/4)(4) + b
-2 = 3 + b
-5 = b
b = -5
The equation is
y = 3/4 x - 5
Let x = number of adult tickets sold
Let x-53 = number of student tickets sold
x + x -53 = 697
2x - 53 = 697.
Add 53 to both sides to get:
2x = 750
Divide both sides by 2 to get:
x = 375
375 adult tickets were sold.
