What can form compounds from nitrogen in the air?

Which best explains why sawdust burns more quickly than a block of wood of equal mass under the same conditions?

hammer [34]

More molecules in the sawdust can collide with oxygen molecules

8 0

3 years ago

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An ionic compound is formed when there is a reaction between the elements

Ivan

<span>In order for an ionic compound to be created, there has to be a reaction between a metal and a non-metal. Having this in mind, the correct answer is A. strontium and chlorine. Strontium (Sr) is an alkaline earth metal, whereas chlorine (Cl) is a halogen gas, so a non-metal. There is no this type of a combination of metal + non-metal in other options, so only A is correct.</span>

4 0

3 years ago

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A laboratory Instructor gives a sample of arnIno-acid powder to each of four students, I, II. III, and iv. and they weigh the sa

Charra [1.4K]

Answer:

1:

Explanation:

6 0

3 years ago

Draw the product formed by the reaction of t-butoxide with (1r,2s)-1-bromo-2-methyl-1-phenylbutane (shown below). (draw the corr

zepelin [54]

https://goo.gl/images/Zs316J go here to get the anwser you are looking for.

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3 years ago

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If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.

kicyunya [14]

Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

$CH_{3}COOH \ \textless \ ---\ \textgreater \ H^{+} + CH_{3}COO^{-}$

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> $[H^{+}]$ = $10^{-2.88}$ = 0.001 $moldm^{-3}$

The change in Concentration Δ $[CH_{3}COOH]$ = 0.001 $moldm^{-3}$

  CH3COOH H+ CH3COOH
Initial   $moldm^{-3}$      $x$ 0 0

Change $moldm^{-3}$ -0.001 +0.001 +0.001

Equilibrium $moldm^{-3}$ $x$ - 0.001 0.001 0.001


Since the $k_{a}$ value is so small, the assumption
$[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium}$ can be made.

$k_{a} = [tex]= 1.8*10^{-5} = \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} = \frac{0.001^{2}}{x}$

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps!

8 0

4 years ago