Draw the product formed by the reaction of t-butoxide with (1r,2s)-1-bromo-2-methyl-1-phenylbutane (shown below). (draw the corr
ect stereoisomer of the product.)
2 answers:
Answer:
(E)-(2-methylbut-1-en-1-yl)benzene
Explanation:
This reaction is an E2 elimination reaction, it involves a single-step mechanism. In the single step mechanism, the required geometry is an anti-peri-planar geometry. In other words, the required configuration is a configuration for the leaving group and the H that would be removed. The leaving group and the hydrogen must now be of an opposite configuration when the base attacks the hydrogen.
Hence the stereo chemistry of the product (E)-(2-methylbut-1-en-1-yl)benzene shown below.
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Answer:
The answer is "Greater than zero, and greater than the rate of the reverse reaction".
Explanation:
It applies a rate of reaction to the balance, a forward response dominates until it reaches a constant. This process is balanced before 52 mmol of the reactant, to which 3 is added. In balance, that rate of the forward reaction was its rate with forwarding reaction, both of which are higher than 0 as the response has achieved balance so that both species get a level greater than 0.