Draw the product formed by the reaction of t-butoxide with (1r,2s)-1-bromo-2-methyl-1-phenylbutane (shown below). (draw the corr
ect stereoisomer of the product.)
2 answers:
Answer:
(E)-(2-methylbut-1-en-1-yl)benzene
Explanation:
This reaction is an E2 elimination reaction, it involves a single-step mechanism. In the single step mechanism, the required geometry is an anti-peri-planar geometry. In other words, the required configuration is a configuration for the leaving group and the H that would be removed. The leaving group and the hydrogen must now be of an opposite configuration when the base attacks the hydrogen.
Hence the stereo chemistry of the product (E)-(2-methylbut-1-en-1-yl)benzene shown below.
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Answer : The structure of will be square-planar.
Explanation :
In the given molecule , 'Xe' is the central atom and 'H' is the terminal atom.
Xenon has 8 valence electrons and hydrogen has 1 valence electron. Therefore, the total number of valence electrons are 8 + 4(1) = 12 electrons.
The number of electrons used in Xe-H bonding = 8 electrons
The remaining electrons which are used as lone pair on central atom (Xe) = 12 - 8 = 4 electrons
There are 4 bonding pairs and 2 lone pairs of electrons, they will be arranged in the octahedral arrangement around the central atom with 2 lone pairs of electrons on central atom. The lone pairs are arranged linearly across the central atom. The resulting structure will be square-planar.
The structure of is shown below.
