Draw the product formed by the reaction of t-butoxide with (1r,2s)-1-bromo-2-methyl-1-phenylbutane (shown below). (draw the corr
ect stereoisomer of the product.)
2 answers:
Answer:
(E)-(2-methylbut-1-en-1-yl)benzene
Explanation:
This reaction is an E2 elimination reaction, it involves a single-step mechanism. In the single step mechanism, the required geometry is an anti-peri-planar geometry. In other words, the required configuration is a configuration for the leaving group and the H that would be removed. The leaving group and the hydrogen must now be of an opposite configuration when the base attacks the hydrogen.
Hence the stereo chemistry of the product (E)-(2-methylbut-1-en-1-yl)benzene shown below.
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Answer:
pH = 11.216.
Explanation:
Hello there!
In this case, according to the ionization of ammonia in aqueous solution:
We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:
However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:
Which is also:
Thereafter we can compute the pOH first:
Finally, the pH turns out:
Regards!