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Over [174]
4 years ago
13

How would you prepare 500 ml of a 0.2% solution of the detergent Tween-20? This reagent is a liquid in its pure state.

Chemistry
1 answer:
Anastasy [175]4 years ago
6 0

Answer:

At a 500 mL volumetric ballon, it will be added a little of distilled water, then 1 mL of the pure detergent, and then it will be added water until the meniscus. The solution will be agitated by inverting the flask until it's homogeneous.

Explanation:

In its pure state, the detergent has a 100% concentration. Thus, knowing that the product of the concentration by volume must be constant, we can do:

C1V1 = C2V2

Where C is the concentration, V is the volume, 1 is the pure detergent, and 2 the solution. So, let's find the volume of pure detergent needed to prepare 500 mL of the solution:

100*V1 = 0.2*500

100V1 = 100

V1 = 1 mL

Thus, at a 500 mL volumetric ballon, it will be added a little of distilled water, then 1 mL of the pure detergent, and then it will be added water until the meniscus. The solution will be agitated by inverting the flask until it's homogeneous.

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KE and PE Math
slava [35]

Answer:

1. Answer: The bowling ball has more potential energy as it sits on top of the building. It does not have any kinetic energy because it is not moving.

2. Answer: The bowling ball has equal amounts of potential and kinetic energy half way through the fall. At the half way point, half of the potential energy has been converted to kinetic energy.

3. Answer: Just before the ball hits the ground, it has more kinetic energy. As it hits the ground the potential energy becomes zero.

4. Answer:

PE=784 J

5. Answer:  

PE = 392 J

6. Answer:

KE= 392 J

Also, since the PE and KE are equal at the half way point and PE =392 J, KE = 392 J.

7. What is the kinetic energy of the ball just before it hits the ground?

Answer:  

KE=784 J

At first I answered in the comments, but I am able to answer now. I hope this can help

6 0
4 years ago
What is the molarity of a solution that contains 1 mol CaCl2 dissolved in 2 L of solution?
SVETLANKA909090 [29]

Answer:

molarity= 0.5M

Explanation:

n=CV

n= 1mol, C= ?, V= 2L

1= C×2

C= 0.5M

5 0
3 years ago
What is the total number of valence electrons in the propylene molecule??
Nonamiya [84]
18 valance electrons, Hope this helps!

8 0
4 years ago
Question 3(Multiple Choice Worth 4 points)
mash [69]

Answer:

It donates a hydrogen ion

Explanation:

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4 years ago
Read 2 more answers
A chemical equation is shown below. KNO3 → KNO2 + O2 What are the coefficients that should be added to balance this equation? Us
uysha [10]

20) Balanced chemical equation: 2KNO₃ → 2KNO₂ + O₂.

Potassium nitrate is decomposed on potassium nitrite and oxygen.

According to principle of mass conservation, number of atoms must be equal on both side of chemical reaction.  

There are two potassium atoms, two nitrogen atoms and six oxygen atoms on both side of balanced chemical reaction.  

Decomposition is reaction where one substance (in this example potassium nitrate) is broken down into two or more simpler substances (potassium nitrite and oxygen).  

21) The answer is:

Balanced chemical reaction: double recplacement reaction.

MgCl₂(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2NaCl(aq).

The magnesium (Mg) and the sodium (Na) replace each other making this a double replacement reaction.

Reactivity series is an empirical progression of a series of metals, arranged by their reactivity from highest to lowest (alkaline metals have highest reactivity and Noble metals lowest reactivity):  

K > Ba > Sr > Na > Ca > Mg > Be > Al > Mn > Zn > Cr> Fe > Cd > Co > Ni > Sn > Pb > H(in acids) > Cu > Hg > Ag.

Metal higher in the reactivity series will displace another and it will be oxidized.

Magnesium is higher it this series than aluminium and aluminium is higher than copper.

22) The answer is: half life is 22 years.

Half-life is the time required for a quantity (in this example mass of the element) to reduce to half its initial value and is independent of initial concentration.

Mass of the element is reduced by half in 22 years from 45 grams to 22.5 grams.

First calculate the radioactive decay rate constant λ:

λ = 0.693 ÷ t.

λ  = 0.693 ÷ 22 y.

λ = 0.0315 1/y.

ln(m/m₀) = -λ·t₁.

ln(4.8125/308) = -0.0315 1/y · t₁.

t₁ = 132.02 y.

7 0
3 years ago
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