Question

F(x)-x^2+6x+8 how do you convert this form to standard form and vertex form

Answer 1

You complete the square 

Vertex form is 

$f(x) = (x - h)^2 + k~~~~~~~the~~vertex ~~is~~(h, k)$

so break it into parts

$f(x) = (x^2 + 6x + ??) + 8 - ??$

to keep the equation in balance to add and subtract the same value

so value ?? is 

$?? = ( \frac{6}{2} )^2$

then factor the perfect square