The <em>rigid</em> transformations used for each figure:
- Figure 5 - Reflection around x and y axes: (x, y) → (- x, - y)
- Figure 6 - Horizontal and vertical translations: (x, y) → (x + 1, y - 2)
<h3>What transformation rules do create the resulting images?</h3>
In this question we must determine what kind of <em>rigid</em> transformations generates each image. <em>Rigid</em> transformations are transformations applied on geometric loci such that <em>Euclidean</em> distance is conserved. Now we proceed to determine the transformation rule for each case:
Figure 5 - Reflection around the x-axis followed by reflection around the y-axis.
(x, y) → (- x, - y)
Figure 6 - Translation one unit in the +x direction and two units in the -y direction.
(x, y) → (x + 1, y - 2)
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Answer:
Well, it's pretty simple. If your reflecting something over the y axis the X will change if it's negative or positive. So if it's -x and you flip it over it becomes a positive x. If you flip it over the x-axis the Y is the one that change to a negative or positive.
So if the shape flips over the y-axis, the X points will turn negative. for example, one of the points is (1,4) it will turn to (-1,4)
Step-by-step explanation:
Answer:
Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.
Step-by-step explanation:
i) let the number of 2 point question is x.
ii) let the number of 5 point questions be y
iii) total number of questions is 50
iv) therefore x + y = 50
v) it is also given that 2x + 5y = 145
vi) solving for the two equations found in iv) and v). Multiplying iv) by 2 we get
2x + 2y = 100
vii) subtracting equation vi) from equation v) we get 3y = 45.
viii) Therefore y = 15.
ix) using the value in viii) and substituting in iv) we get x + 15 = 50.
Therefore x = 50 - 15 = 35
x) Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.
Answer:
2.835
3.330
Step-by-step explanation:
Let the linear approximation be L(x) at a = 0. This is given by
is the derivative of 
. To find this, we use the form
If 
, then 
By doing this and applying chain rule for the power (which is a function of x), we have
Then
Also 
Hence 
For 
, 
and 
Using this in 
,
For 
, 
and 
Using this in ,
