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Allushta [10]
3 years ago
13

Is 0.416 terminating or repeating

Mathematics
1 answer:
ollegr [7]3 years ago
4 0

terminating................. because the number does not repeat

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A traffic helicopter descends 102 meters to be 331 meters above the ground, as illustrated in the diagram to the right. Write an
lana66690 [7]

Answer:

  • h -102 = 331
  • h = 433

Step-by-step explanation:

Using the problem statement as the basis for the equation, we can write ...

  h -102 = 331

__

Using the diagram as the basis for the equation, we could write it as ...

  h = 331 +102

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The original height of the helicopter was 433 m.

3 0
2 years ago
i need help with this and i just copy and paste it.Beth's mother made some cookies. She put 4 cookies on each of 8 plates. Which
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Answer:

4x8=32

Step-by-step explanation:

6 0
3 years ago
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PLEASE HELP FAST!!! How many solutions does this system have?
Aneli [31]

Step-by-step explanation:

  • y=3/4x+(-5)
  • -4x+4(3/4x+-5)=-20

-4x+3x-20=-20

-x=-20+20

-x=0

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y=-5

5 0
3 years ago
Write the domain and range of the given figure.
Whitepunk [10]
Domain x < or equal to 5
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2 years ago
An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random
Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters  = 12

Total number of blue  highlighters  = 6

Total number of green highlighters  = 4

Total number of orange  highlighters  = 3

So, the total number of highlighters  =  12 + 6 + 4 + 3  = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1)  = \frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}  = \frac{12}{25}

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1  = 11

Also, the number of blue highlighter  =  6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2)  =

\frac{\textrm{Total number of yellow  + Blue   highlighters}}{\textrm{Total Highlighters}} = \frac{17}{25}

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0
3 years ago
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