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Vesnalui [34]
3 years ago
10

An exam worth 145 points contains 50 questions. The number of two-point questions is equal to 50 minus the number of five-point

questions. Some of the questions are worth two points and some are worth five points. How many two-point questions are on the test? How many five-point questions are on the test?
Mathematics
2 answers:
abruzzese [7]3 years ago
3 0

Answer:

Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.

Step-by-step explanation:

i) let the number of 2 point question is x.

ii) let the number of 5 point questions be y

iii) total number of questions is 50

iv) therefore x + y = 50

v) it is also given that 2x + 5y = 145

vi) solving for the two equations found in iv) and v). Multiplying iv) by 2 we get

    2x + 2y = 100

vii) subtracting equation vi) from equation v) we get 3y = 45.

viii) Therefore y = 15.

ix) using the value in viii) and substituting in iv) we get x + 15 = 50.

    Therefore x = 50 - 15  = 35

x) Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.

Katyanochek1 [597]3 years ago
3 0

Answer:

Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.

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If (a,1),(-2,b).(c,-3) are points on the straight line 2x + y = 3x - y +1. Find the values of a, b and c. THANK YOU FOR THR PERS
Lisa [10]

Answer:

it’s g ! i just turned it in and it’s g :)

6 0
3 years ago
What is the simplified form of the following expression 7(^3√2x)-3(^3√16x)-3(^3√8x)
svlad2 [7]

Answer:

The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

Step-by-step explanation:

Given : Expression 7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

To Simplified : The expression

Solution :  

Step 1 - Write the expression

7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

Step 2- Simplify the roots and re-write as

16=2^3\times2 and 8=2^3

7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}

Step 3- Solve the multiplication

7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}

Step 4- Taking \sqrt[3]{2x} common from first two terms

\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}

\sqrt[3]{2x}-6\sqrt[3]{x}

Therefore, The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

5 0
3 years ago
Read 2 more answers
Solve for y<br> 5y - 9 = -3y + 7
Ostrovityanka [42]
The answer is 2 !!!!!!!!!!!
4 0
2 years ago
Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by the given curves
Vadim26 [7]

The expression on the left side describes a parabola. Factorize it to determine where it crosses the y-axis (i.e. the line x = 0) :

-3y² + 9y - 6 = -3 (y² - 3y + 2)

… = -3 (y - 1) (y - 2) = 0

⇒   y = 1   or   y = 2

Also, complete the square to determine the vertex of the parabola:

-3y² + 9y - 6 = -3 (y² - 3y) - 6

… = -3 (y² - 3y + 9/4 - 9/4) - 6

… = -3 (y² - 2•3/2 y + (3/2)²) + 27/4 - 6

… = -3 (y - 3/2)² + 3/4

⇒   vertex at (x, y) = (3/4, 3/2)

I've attached a sketch of the curve along with one of the shells that make up the solid. For some value of x in the interval 0 ≤ x ≤ 3/4, each cylindrical shell has

radius = x

height = y⁺ - y⁻

where y⁺ refers to the half of the parabola above the line y = 3/2, and y⁻ is the lower half. These halves are functions of x that we obtain from its equation by solving for y :

x = -3y² + 9y - 6

x = -3 (y - 3/2)² + 3/4

x - 3/4 = -3 (y - 3/2)²

-x/3 + 1/4 = (y -  3/2)²

± √(1/4 - x/3) = y - 3/2

y = 3/2 ± √(1/4 - x/3)

y⁺ and y⁻ are the solutions with the positive and negative square roots, respectively, so each shell has height

(3/2 + √(1/4 - x/3)) - (3/2 - √(1/4 - x/3)) = 2 √(1/4 - x/3)

Now set up the integral and compute the volume.

\displaystyle 2\pi \int_{x=0}^{x=3/4} 2x \sqrt{\frac14 - \frac x3} \, dx

Substitute u = 1/4 - x/3, so x = 3/4 - 3u and dx = -3 du.

\displaystyle 2\pi \int_{u=1/4-0/3}^{u=1/4-(3/4)/3} 2\left(\frac34 - 3u\right) \sqrt{u} \left(-3 \, du\right)

\displaystyle -12\pi \int_{u=1/4}^{u=0} \left(\frac34 - 3u\right) \sqrt{u} \, du

\displaystyle 12\pi \int_{u=0}^{u=1/4} \left(\frac34 u^{1/2} - 3u^{3/2}\right)  \, du

\displaystyle 12\pi \left(\frac34\cdot\frac23 u^{3/2} - 3\cdot\frac25u^{5/2}\right)  \bigg|_{u=0}^{u=1/4}

\displaystyle 12\pi \left(\frac12 u^{3/2} - \frac65u^{5/2}\right)  \bigg|_{u=0}^{u=1/4}

\displaystyle 12\pi \left(\frac12 \left(\frac14\right)^{3/2} - \frac65\left(\frac14\right)^{5/2}\right) - 12\pi (0 - 0)

\displaystyle 12\pi \left(\frac1{16} - \frac3{80}\right) = \frac{12\pi}{40} = \boxed{\frac{3\pi}{10}}

6 0
2 years ago
PLEASE ANSWER NUMBER 32!!!
Leni [432]

Answer:

N < -3

Step-by-step explanation:

first off, simply, then subtract the 9s from both sides.

5n < -6 -9

Simplify -6 -9 to -15 , Which gives you

5n < -15

then, divide both sides by 5.

n < 15/5

Simplify 15/5 to 3, Which give you

N < -3

here is your answer.

N < -3

8 0
2 years ago
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