Answer:
He did not wait as long between each treatment of ant killer.
Step-by-step explanation:
He did one on monday and another on saturday then checked them on sunday
Answer:
Step-by-step explanation:
the perimeter of the semi-circle would be the diameter plus the circumference of half of the circle.
They want to know the perimeter of a square using the diameter of the sem-circle as ONE side, so the perimeter of the square would be 4 times the ONE side.
We should recall:
diameter = 2 times the radius circumference of a cirlce = 2π r
How do we find the diameter of the of the semi circle?
The perimeter of the semi circle is given as 108 cm
Perimeter of the semicirle = 2r + π r diameter plus semi circumference
108 = r ( 2 + π) factor out the r and solve for r
108 / (2 + π) = r divide both sides by ( 2 + r)
Now we know r, the perimeter of the squqre is 4 times 2r or 8r
perimeter of square = 8 [ 108 / (2 + π) ] π I used 3.14
= 864 / 5.14
= 168.1 cm I got rounded to nearest tenth
<em>When I re-checked by work I found a few math, logic and calculation errors. Please re-check my answer for any more mistakes.</em>
Answer:
A is the Answer.
Step-by-step explanation:
You multiply x with 2x ( Gives you 2x^2 ) then -1 with 2x ( Gives you -2x ) then -8 with x ( Gives you -8x ) then -1 with-8 ( Gives you +8 ), finally you add the two x's ( not x^2 ). Your fibal answer will be 2x^2 - 10x +8.
Hope this helps.
Answer:
1. |y| sqrt(10)
2. |x| sqrt(x)
3. a^2 sqrt(a)
4. 4 |y|^3 sqrt(3)
5. 1/4 *|x| sqrt(3x)
Step-by-step explanation:
1. sqrt(10y^2)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(y^2) sqrt(10)
|y| sqrt(10)
We take the absolute value of y because -y*-y = y^2 and the principle square root is y
2. sqrt(x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(x^2) sqrt(x)
|x| sqrt(x)
3. sqrt(a^5)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(a^4) sqrt(a)
a^2 sqrt(a)
4. sqrt(16 y^7)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(16) sqrt(y^6)sqrt(y)
4 |y|^3 sqrt(3)
5. sqrt(3/16x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(1/16) sqrt(x^2)sqrt(3x)
1/4 *|x| sqrt(3x)
