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bekas [8.4K]
3 years ago
15

Evaluate 1 3/7-(2/3+5/7)​

Mathematics
2 answers:
Artyom0805 [142]3 years ago
7 0

Answer:

13/7 - (14/21 + 15/21)

Step-by-step explanation:

= 13/7 - ( 29/21)

= 39/21 - 29/21 = 10/21 = 0.47

KATRIN_1 [288]3 years ago
6 0

Answer:

that's the answer .......

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A test for the presence of a certain disease has probability 0.2 of giving a false-positive result (indicating that an individua
drek231 [11]
For the part b of the question please find the attached image.

4 0
3 years ago
Function f is shown on the graph below where two points are marked. If function f is horizontally compressed by a factor of 2, p
lilavasa [31]

Answer:

If you have    

f(x) = x^2

The point  (2,4)   would be transformed to (1,1)

Step-by-step explanation:

If your compression is horizontal then the transformation you are making is the following

g(x)  = f(x/2)

Therefore, if you have    

f(x) = x^2

The point  (2,4)   would be transformed to (1,1)

5 0
3 years ago
Write the repeating decimal as a fraction
olga_2 [115]

Answer:

The correct answer is: \frac{37}{90}

Step-by-step explanation:

You're using Acellus, right?

Let me guess: Algebra I?

3 0
3 years ago
Read 2 more answers
Please see attachment
ycow [4]

Answer:

Relation 1: Not a function

Relation 2: Not a function

Relation 3: Function

Relation 4: Not a function

Step-by-step explanation:

Recall: a relation can only be a function if and only if each domain value has only 1 range value mapped to it or related to it. This means that a domain value can only have exactly one range value for the relation to be qualified a function.

✔️Relation 1 is NOT A FUNCTION.

Rationale: Two of the domain values (star and sky) is having more than 1 range value assigned to each.

✔️Relation 2 is NOT A FUNCTION:

Rationale: domain value, 9, has several range values assigned to it.

✔️Relation 3 is A FUNCTION:

Rationale: each domain value do not have more than one range values assigned to it.

✔️Relation 4 IS NOT A FUNCTION:

Rationale: the domain value, 6, has two range values, m and d, assigned to it.

6 0
3 years ago
Rewrite the quadratic function in vertex form.<br> Y=3x^2-12x+4
chubhunter [2.5K]

Answer:

\large\boxed{y=3(x-2)^2-8}

Step-by-step explanation:

The vertex form of an equation of a parabola y = ax² + bx + c:

f(x)=a(x-h)^2+k

(h, k) - vertex

h=\dfrac{-b}{2a},\ k=f(h)

We have the equation:

y=3x^2-12x+4\\\\a=3,\ b=-12,\ c=4

Substitute:

h=\dfrac{-(-12)}{2(3)}=\dfrac{12}{6}=2\\\\k=f(2)=3(2^2)-12(2)+4=3(4)-24+4=12-24+4=-8

Finally:

y=3(x-2)^2+(-8)=3(x-2)^2-8

4 0
3 years ago
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