C = 2m^2 + m
D = 2 - 6m + 2m^2
2C = 2(2m^2 + m) = 4m^2+2m
2D = 2(2-6m+2m^2) = 4-12m+4m^2
2C - 2D =
4m^2+2m-(4-12m+4m^2) =
4m^2+2m-4+12m-4m^2 =
0m^2 + 14m -4 =
14m - 4
The goal is to solve for y. Start by subtracting 2x from both sides. This gives you 8y=-2x+16. Now just divide both sides by 8, which gives you y=-2/8x+16/8. Finally, simplify this to y=-1/4x+2.
Answer: 3
Step-by-step explanation:
8-5= 3.
4-3=1
so it’s 3/1 or 3
It should be represented into a Jorge
Answer/Step-by-step explanation:
Question 1:
Interior angles of quadrilateral ABCD are given as: m<ABC = 4x, m<BCD = 3x, m<CDA = 2x, m<DAB = 3x.
Since sum of the interior angles = (n - 2)180, therefore:

n = 4, i.e. number of sides/interior angles.
Equation for finding x would be:



(dividing each side by 12)

Find the measures of the 4 interior angles by substituting the value of x = 30:
m<ABC = 4x
m<ABC = 4*30 = 120°
m<BCD = 3x
m<BCD = 3*30 = 90°
m<CDA = 2x
m<CDA = 2*30 = 60°
m<DAB = 3x
m<DAB = 3*30 = 90°
Question 2:
<CDA and <ADE are supplementary (angles on a straight line).
The sum of m<CDA and m<ADE equal 180°. To find m<ADE, subtract m<CDA from 180°.
m<ADE = 180° - m<CDA
m<ADE = 180° - 60° = 120°