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Rom4ik [11]
3 years ago
8

In the equilateral triangle XYZ, X is located at (-5, -9) and Z is located at (1, -17). What is the perimeter of Triangle XYZ? a

30 units b 10 units c 25 units d 5 units
Mathematics
1 answer:
mario62 [17]3 years ago
3 0

Answer:

Option a. 30 units

Step-by-step explanation:

we know that

An equilateral triangle has three equal sides

so

XY=YZ=XZ

The perimeter of triangle XYZ is equal to

P=XY+YZ+XZ

P=3XZ

<u><em>Find the distance XZ</em></u>

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

X is located at (-5, -9) and Z is located at (1, -17)

substitute the values in the formula

XZ=\sqrt{(-17+9)^{2}+(1+5)^{2}}

XZ=\sqrt{(-8)^{2}+(6)^{2}}

XZ=\sqrt{100}

XZ=10\ units

Find the perimeter

P=3(10)=30\ units

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10:9

Step-by-step explanation:

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3 years ago
A party rental company has chairs and tables for rent. The total cost to rent 3 chairs and 5 tables is $52. The total cost to re
riadik2000 [5.3K]

Answer:

The cost for 1 chair is $2.75 and the cost for 1 table is $8.75

Step-by-step explanation:

Use the elimination method of linear equations to find your answer.

Our equations for this problem are:

3c+5t=52 and 9c+7t=86

1. Multiply the entire first equation by -3.

-3(3c+5t=52)

2. Simplify the equation from above:

-9c-15t=-156

3. Stack the two equations on top of each other and add/subtract:

-9c-15t=-156

9c+7t=86

4. You should be left with -8t=-70. Simplify this to find the value of t:

t=8.75

5. Plug the value of t into any of the original equations and solve for c.

3c+5(8.75)=52

6. Simplify the equation above:

3c+43.75=52

7. Subtract 43.75 from both sides of the equation:

3c=8.25

8. Divide both sides by 3 to get your c value:

c=2.75

3 0
3 years ago
A Rectangular has area 12a^2 and perimeter 14a what are the dimensions of this Rectangular?​
Nataliya [291]

9514 1404 393

Answer:

  3a by 4a

Step-by-step explanation:

For dimensions L and W, the area and perimeter are ...

  A = LW = 12a^2

  P = 2(L+W) = 14a

Using the second equation, we can find L:

  L +W = 7a . . . . . divide by 2

  L = 7a -W

Substituting into the area formula gives the quadratic ...

  (7a -W)(W) = 12a^2

  W^2 -7aW +12a^2 = 0 . . . . arrange in standard form

  (W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)

Then we have the two solutions ...

  W = 3a, L = 4a

  W = 4a, L = 3a

The rectangle dimensions are 3a by 4a.

5 0
3 years ago
The distance between two points is 6_/6.One endpoint is (4,-1). It is known that the y-coordinate of the other endpoint is 9.
babunello [35]

The x-coordinate of the given endpoint will be "x = 4 \pm 2\sqrt{29}".

According to the question,

The end points are:

  • (x_1,y_1) = (4,-1)
  • (x_2, y_2) = (x,9)

Distance,

  • 6\sqrt{6}

As we know,

The distance formula,

→ Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

By substituting the values, we get

→         6\sqrt{6} = \sqrt{(x-4)^2+(9+1)^2}

→          216= (x-4)^2+100

→   (x-4)^2 = 116

→       x-4 = \pm \sqrt{116}

→       x-4=\pm 2\sqrt{29}

→             x = 4 \pm 2\sqrt{29}                

Thus the above answer is right.  

Learn more:

brainly.com/question/18310956

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Which are perfect squares check all that apply 72 36 8 16 81 64 48​
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Answer:36 16

Step-by-step explanation:

4 0
3 years ago
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